Question

因此，当执行下面的SQL时，我得到以下内容：字符串或二进制数据将被截断。

EXEC sp_GoodsWelcomeNotification 'd84be19b-be86-4a38-958b-e6d786cc27db'

存储过程如下：

ALTER PROC [dbo].[sp_GoodsWelcomeNotification](
@ItemGuid VARCHAR(50)
)

AS
DECLARE @ProductCode VARCHAR(50), @ParentGuid VARCHAR(100)
    SET @ProductCode = 'SELECT Idx37 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=' + @ItemGuid
    SET @ParentGuid = 'SELECT Idx134 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=' + @ItemGuid

BEGIN TRANSACTION
    INSERT INTO NotificationTable
    VALUES(650, @ProductCode, @ParentGuid, 'PENDING','','','Y','Y',@ItemGuid,0,'','')
COMMIT TRANSACTION

当我手动执行insert语句时，它执行正常：

INSERT INTO NotificationTable
    VALUES(650, 'BV-TKM-0000068-02', '241c8abc-5f95-4c35-9405-d6adfc8e2f55', 'PENDING','','','Y','Y','d84be19b-be86-4a38-958b-e6d786cc27db',0,'','')

我哪里错了？

Answer 1

此语法不正确：

SET @ProductCode = 'SELECT Idx37 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=' + @ItemGuid
SET @ParentGuid = 'SELECT Idx134 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=' + @ItemGuid

我认为你在寻找：

SELECT @ProductCode = Idx37 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=@ItemGuid
SELECT @ParentGuid = Idx134 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6=@ItemGuid

您将SELECT语句分配给变量，而不是select语句的结果

或者更简单的查询是：

SELECT 
    @ProductCode = Idx37,
    @ParentGuid = Idx134
FROM 
    iwfAccountOpening 
WHERE 
    Idx1!='' 
    AND Idx6=@ItemGuid

Answer 2

试试这个，

ALTER PROC [dbo].[sp_GoodsWelcomeNotification](
@ItemGuid VARCHAR(50)
)

AS
DECLARE @ProductCode VARCHAR(50), @ParentGuid VARCHAR(100)
SET @ProductCode = (SELECT Idx37 FROM iwfAccountOpening WHERE Idx1!='' AND      Idx6= @ItemGuid)
SET @ParentGuid = (SELECT Idx134 FROM iwfAccountOpening WHERE Idx1!='' AND Idx6= @ItemGuid)

BEGIN TRANSACTION
INSERT INTO NotificationTable
VALUES(650, @ProductCode, @ParentGuid,   'PENDING','','','Y','Y',@ItemGuid,0,'','')
COMMIT TRANSACTION

存储过程不起作用，手动更新工作正常 - 为什么？

2 个答案: