Question

我正在开发一个购物应用程序，在我的应用程序中我有表租户，在租户表中我有列Binary_id，它是数据库中二进制表的主键。现在，当我向租户表发出get请求时，我将所有租户表字段作为JSON。但我有从二进制表到租户的@ManyToOne关系，即租户可以有多个二进制记录。因此，在从POSTMAN客户端进行GET调用而不是获取租户详细信息时，我需要将与该租户相关的所有二进制记录作为JSON。

现在，当我从POSTMAN客户端

调用http://localhost:8080/sportsmvc/rest/tenant时，我将获得如下JSON

[
{
"id": 2,
"binaryId": "1002",
"name": "AltisArena"
},
{
"id": 9,
"binaryId": "1001",
"name": "Agon"

} ]

但我需要响应JSON如下：

      [
    {
        "id": 2,
        "name": "AltisArena",
        "listOfBinary": [
            {
                "tenant_id": 2,
                "location": "location1",
                "description": "ABC"
            },
            {
                "tenant_id": 2,
                "location": "location2",
                "description": "ABCD"
            }
        ]
    },
    {
        "id": 9,
        "name": "Agon",
        "listOfBinary": [
            {
                "tenant_id": 9,
                "location": "location3",
                "description": "desc1"
            },
            {
                "tenant_id": 9,
                "location": "location4",
                "description": "desc2"
            }
        ]
    }
]

代码段：

租户实体：

    @Entity
@Table(name="tenant", catalog="db_sports" )
// Define named queries here
@NamedQueries ( {
  @NamedQuery ( name="TenantEntity.countAll", query="SELECT COUNT(x) FROM TenantEntity x" )
} )
public class TenantEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    //----------------------------------------------------------------------
    // ENTITY PRIMARY KEY ( BASED ON A SINGLE FIELD )
    //----------------------------------------------------------------------
    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    @Column(name="id", nullable=false)
    private Integer    id           ;
    @Column(name="name", nullable=false, length=300)
    private String     name         ;

   //----------------------------------------------------------------------
   // ENTITY LINKS ( RELATIONSHIP )
   //----------------------------------------------------------------------
   @ManyToOne
   @JoinColumn(name="binary_id", referencedColumnName="id")
   private SwaBinaryEntity swaBinary   ;

SWA_Binary实体：

       @Entity
@Table(name="SWA_Binary", catalog="db_sports" )
// Define named queries here
@NamedQueries ( {
  @NamedQuery ( name="SwaBinaryEntity.countAll", query="SELECT COUNT(x) FROM SwaBinaryEntity x" )
} )
public class SwaBinaryEntity implements Serializable {

    private static final long serialVersionUID = 1L;

    //----------------------------------------------------------------------
    // ENTITY PRIMARY KEY ( BASED ON A SINGLE FIELD )
    //----------------------------------------------------------------------
    @Id
    @Column(name="id", nullable=false, length=100)
    private String     id           ;

    @Column(name="file_location", nullable=false, length=400)
    private String     fileLocation ;

    @Column(name="description", nullable=false, length=200)
    private String     description  ;

TenantRestController：

   @RequestMapping( value="/tenant",
        method = RequestMethod.GET,
        produces = MediaType.APPLICATION_JSON_VALUE)
@ResponseStatus(HttpStatus.OK)
@ResponseBody
public List<Tenant> findAll() {
    return tenantService.findAll();
}

TenantServiceImpl：

@Override
public List<Tenant> findAll() {
    List<TenantEntity> entities = tenantPersistence.loadAll();
    List<Tenant> beans = new ArrayList<Tenant>();
    for(TenantEntity entity : entities) {
        beans.add(tenantServiceMapper.mapTenantEntityToTenant(entity));
    }
    return beans;
 }

TenantServiceMapper：

public Tenant mapTenantEntityToTenant(TenantEntity tenantEntity) {
    if(tenantEntity == null) {
        return null;
    }

    //--- Generic mapping 
    Tenant tenant = map(tenantEntity, Tenant.class);

    //--- Link mapping ( link to SwaBinary )
    if(tenantEntity.getSwaBinary() != null) {
        tenant.setBinaryId(tenantEntity.getSwaBinary().getId());
    }
    return tenant;
}

任何人都可以帮助解决这个问题。

先谢谢。

Answer 1

也许我误解了模特，但似乎有点不对劲。在您需要JSON的情况下，您拥有多个二进制文件的租户，但在JPA模型中，它反之亦然，租户有一个二进制文件。

TenantEntity不应该这样吗？：

@OneToMany
private List<SwaBinaryEntity> swaBinary

使用SpringMVC

1 个答案: