Question

这是我的表单代码的第一位

 <form action="PHP/form.php" id="msform" method="post">

<fieldset id="owner_service">
<h2> ARE YOU A DOG OWNER OR SERVICE PROVIDER?</h2>
<legend>owner_service</legend>
<div class="owner_service">
<input type="radio" id="service" name="owner_service" value="service">
<label for ="service"><h5>SERVICE PROVIDER</h5></label>
<input type="radio" id="owner" name="owner_service" value="owner">
<label for ="owner"><h5>DOG OWNER</h5></label>
</div>
<input type="button" name="next" class="next action-button" id="next" value="NEXT" />
</fieldset>

这里是PHP

  <?php
session_start();

$servername = "";
$username = "";
$password = "";
$dbname = "";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 


$sql = "INSERT INTO pets (owner_service, Gender, Age, Size, Location, idealLocation, Service)
VALUES ('{$_POST['owner_service']}', '{$_POST['gender']}', '{$_POST['age']}', '{$_POST['size']}', '$locationCommaString', '{$_POST['ideal_location']}', '{$_POST['service']}')";



if($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}


?>

我的表单已经运行，因此结果在数据库中，但我想要做的是将用户带到新页面，具体取决于他们是否点击了服务提供商＆＃39;或者＆＃39;狗主人＆＃39;。我不知道在哪里放置标题，因为如果我替换我已经拥有的if语句，那么结果将不会显示在我的数据库中。

Answer 1

if(isset($_POST['next'])) {

   // your code to save data 
  // after submit without db error

    if($_POST['owner_service'] == 'service') { // redirect page; }
    else if($_POST['owner_service'] == 'owner') { // redirect page; }

}

将其置于相同的回声范围内＆＃34;成功创建新记录＆＃34;;

Answer 2

if语句在查询执行后发生。与@laimingl建议的相似

Answer 3

 <?php
session_start();

$servername = "";
$username = "";
$password = "";
$dbname = "";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 


$sql = "INSERT INTO pets (owner_service, Gender, Age, Size, Location, idealLocation, Service)
VALUES ('{$_POST['owner_service']}', '{$_POST['gender']}', '{$_POST['age']}', '{$_POST['size']}', '$locationCommaString', '{$_POST['ideal_location']}', '{$_POST['service']}')";



if($conn->query($sql) === TRUE) {
    echo "New record created successfully";
   $serv = $_POST['owner_service'] ;
   switch($serv){
   case 'case 1':
          // Page redirection code here
   break;

   case 'case 2':
   // Page redirection code here
   break;





} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}


?>

Answer 4

只需将input type="button"更改为input type="submit"。

表单提交后PHP重定向到不同的页面

4 个答案: