Question

我试图在名为sizeList的列表中循环并检查条件。代码没有返回正确的值。谁知道问题可能是什么？

overAvg = 0
overTre = 0

avgSize = np.mean(sizeList)

for a in sizeList:
    if a >= avgSize:
        overAvg += 1

treshold = raw_input("Enter Size Treshold: ")

for t in sizeList:
    if t >= treshold:
        overTre += 1


print overAvg
print overTre

for key, value in pktDict.iteritems():
    sizeValue = [value]
    sizeList.append(sizeValue)

工作代码：

for key, value in pktDict.iteritems():
        sizeValue = value
        sizeList.append(sizeValue)

avgSize = np.mean(sizeList)

for a in sizeList: 
   if a >= avgSize:
       overAvg += 1

treshold = int(raw_input("Enter Size Treshold: "))

for t in sizeList:
    if t >= treshold:
        overTre += 1

print overAvg
print overTre

Answer 1

您需要将输入大小转换为... $("#loading-indicator").show(); $.post( "/echo/json/", { delay: 2 }, function(data) { ... $("#loading-indicator").hide(); } ); ...，否则它会比较词汇值而不是数字。此外，从评论中我看到您的列表在每个字段中都有一个大小为1的列表，您需要将其展平（或者首先将列表初始化为1D）：

int

结果：

import numpy as np
overAvg = 0
overTre = 0
sizeList = [[4],[7],[43],[5],[54],[7],[4],[5]] # only formatted like this because OP's list is
sizeList = [item[0] for item in sizeList]
avgSize = np.mean(sizeList)

for a in sizeList:
  if a >= avgSize:
    overAvg += 1

treshold = int(raw_input("Enter Size Treshold: "))

for t in sizeList:
  if t >= treshold:
    overTre += 1


print overAvg
print overTre

在您的代码中，您创建的列表每次迭代只包含一个项目，而您应该这样做：

Enter Size Treshold: 5
2
6

如果条件不起作用，Python在列表中循环

1 个答案: