我加入两个SQL表(applications,areas_application1)并按区域分组。 在第一个表中,我有列url_title和url_link。我想在eah区域显示url_title的列表,并为每个标题添加href链接。我尝试按空间聚合url_title,但我不知道如何为每个url_title聚合url_link。 这个版本不起作用。
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
// function get json from url
// by making HTTP POST or GET mehtod
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
System.out.println(is + "post");
}else if(method == "GET"){
System.out.println("1");
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
System.out.println("2");
String paramString = URLEncodedUtils.format(params, "utf-8");
System.out.println("3");
url += "?" + paramString;
System.out.println("4");
HttpGet httpGet = new HttpGet(url);
System.out.println("5");
HttpResponse httpResponse = httpClient.execute(httpGet);
System.out.println("6");
HttpEntity httpEntity = httpResponse.getEntity();
System.out.println("7");
is = httpEntity.getContent();
System.out.println(is + "get");
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
Log.i("TagCovertS", "["+json+"]");
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
答案 0 :(得分:0)
以下查询应该有所帮助:
SELECT
app.area,
ar.cartodb_id,
count(app.area),
array_to_string(array_agg('<a href="'||app.url_link||'">'||app.url_title||'</a>'),
' '),
ar.the_geom_webmercator
FROM applications as app
JOIN areas_application1 as ar ON ar.name = app.area
GROUP BY app.area, ar.the_geom_webmercator, ar.cartodb_id;