使用angualrjs

时间:2015-05-12 03:54:39

标签: javascript json angularjs html5 web

我是AngularJS的初学者,我被困在我的一个项目中。我希望用户在表单中输入的数据转换为以下格式:<<“schema:data”>>并被推送并显示在json-ld的@graph中。 这是我的html和角度代码:

angular.module("watch", [])

.controller("ctrl", function($scope) {
    $scope.output = {
            "@context": {
            "schema": "http://schema.org/"
			},
           "@graph": [{
            "@id": "person",
			"@type": "schema:Person",
			}
			]
	
    }


    $scope.volatile = {};
    $scope.output["@graph"][0]["schema:givenName"] = "";
	
	
    $scope.$watch(function(scope) {
            return scope.volatile
	
        },
		function(newValue, oldValue) {
          $scope.output = newValue;
		     
			
		
        });
		
})
</script>
head>
    <title>
      reelyActive: Angular Test 
    </title>
	
    <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.13/angular.min.js">
    </script>
    <script type="text/javascript" src="watch.js">
    </script>
	<link rel="stylesheet" href="style.css" />
  </head>
  <body ng-app="watch">
  <ul>
<li><a href="product.html">Product</a></li>
<li><a href="place.html">Place</a></li>

</ul><br/><br/>
    <div ng-controller="ctrl">
      <form>
        GivenName:  
        <input type="text" ng-model="volatile.givenName">
        <br/>
        FamilyName:	
        <input type="text" ng-model="volatile.familyName">
        <br/>
        Gender: 
        <input type="text" ng-model="volatile.gender">
        <br/>
        Nationality:
        <input type="text" ng-model="volatile.nationality">
        <br/>
        WorksFor: 
        <input type="text" ng-model="volatile.worksFor">
        <br/>
        JobTitle:
        <input type="text" ng-model="volatile.jobTitle">
        <br/>
        Url: 
        <input type="text" ng-model="volatile.url">
        <br/>
        Image:
        <input type="text" ng-model="volatile.image">
        <br/>
         </form>
         <h1>
           Your JSON
         </h1>
         <p>
           {{output}} 
         </p>
    </div>
	
	
	
	
  </body>
</html>

1 个答案:

答案 0 :(得分:0)

$scope.output['@graph'].push({
        "@id": "person",
        "@type": "schema:Person",
        });