Question

我有以下模型，我正在尝试使用Django ModelForm的ModelChoiceField来快速解决我的问题

SO_SNDTIMEO

现在，当我尝试保存SettingsForm时，我得到了GameCode ='GameCode Object'而不是像Class Games(Model): code = charField() # GTA, ABC, etc.. name = charField() # Grand Tourismo, ALL BBB CCC , etc.. unique_together(code, name) class Settings(Model): gameCode = charField(). #Didn't use Foreign key because of internal reasons where we can't use Games model somewhere outside username = charField() ... class GameCodeChoiceField(ModelChoiceField): def label_from_instance(self, obj): return obj.name class SettingsForm(forms.ModelForm): gameCode = GameCodeChoiceField(queryset=None,required=False) class Meta: model = Settings fields = ['username'] def __init__(self, *args, **kwargs): super(SettingsForm, self).__init__(*args, **kwargs) self.fields['gameCode'].queryset = Games.objects.filter(game=game, isActive=True) self.fields['gameCode'].to_field_name = 'code'这样的代码..

请帮忙。编辑。

Answer 1

to_field_name更改生成的选项元素的值，而不是显示文本。

您要向模型添加__str__方法。它将更改select元素中列出的每个对象实例的显示。

Class Games(Model):
   code = charField()  # GTA, ABC, etc..
   name = charField()  # Grand Tourismo, ALL BBB CCC , etc..
   unique_together(code, name)

   def __str__(self):
      return self.code

Django ModelChoiceField to_field_name不起作用

1 个答案: