Question

目的确定字符串是否是回文，忽略任何空格，特殊字符和大小写。

JAVASCRIPT

    function palindrome(str) {
  //remove punctuation, whitespace, capitalization, and special characters from original string - 
  var original = str.replace(/[\.,-\/#!$%\^&\*;:{}=\-_`~()]/g,"")
                   .replace(/\s/g," ").toLowerCase();

  //take original sentence and reverse
  var reverse = original.split('').reverse().join('');

  //compare original vs reversed
  if (original == reverse) {
    return true;
  } else {
    return false;
  }

}


palindrome("eye");

问题

我已经通过在线查询创建了上述代码（Palindrome Check）。我错过了什么吗？
我正在使用正则表达式处理punctuation和whitespace并检查出来。

Answer 1

通过将\s包含在字符类中（并添加缺少的常用特殊字符），可以将2个替换链式方法加入到1中：

var original = str.replace(/[\s"'.,-\/#!$%\^&*;:{}=\-_`~()\\\[\]@+|?><]/g,"").toLowerCase();

Answer 2

现在您可以检查任何具有特殊字符（/ n，/ t _，＃，％，2等）的字符串值

function palindrome(str) 
    {

        var re = /[\W_]/g; // getting every special character 
    /*  
        [^A-Z] matches anything that is not enclosed between A and Z

        [^a-z] matches anything that is not enclosed between a and z

        [^0-9] matches anything that is not enclosed between 0 and 9

        [^_] matches anything that does not enclose _  

        /[^A-Za-z0–9]/g  or /[\W_]/g
        */

        str = str.toLowerCase().replace(re, ''); // Remove every specal character
        var len = str.length -1; 
        var mid = Number(len/2);

        for ( var i = 0; i < mid; i++ ) 
        {
            if (str[i] !== str[len - i]) 
            {
                return " Not_Palindrome";
            }
        }

        return "Palindrome";
    }


        var inputValue = "m_ad)am";  // input your Value
        var outPutValue = palindrome(inputValue);
        console.log(" the input value  {" + inputValue + "} is :" + outPutValue);
        //the input value  {madam(} is :Palindrome

检查Palindrome（忽略特殊字符，空格和大小写）

2 个答案: