Question

我是Firebase的新手，所以非常感谢对此的见解。当我以这种方式调用Firebase setValue（obj，callback）函数时，它可以完美地工作。但是，当我试图删除“ref”引用的值时，没有任何反应。这只是一个测试帐户，因此我将安全规则设置为完全读写。输出如下。一些输出来自一个调用removeNode（...）的封装run（）方法。任何见解都非常赞赏。

public void removeNode(final Firebase ref) throws Exception {

    try {
        System.out.println("Start Remove Node: " + ref.toString());

        final AtomicBoolean done = new AtomicBoolean(false);
        ref.removeValue(new Firebase.CompletionListener() {
            @Override
            public void onComplete(FirebaseError firebaseError, Firebase firebase) {
                done.set(true);
                System.out.println("Remove Node complete");
                if (firebaseError != null) {
                    System.out.println("ErrorCode: " + firebaseError.getCode());
                    System.out.println("ErrorMsg: " + firebaseError.getMessage());
                }
                System.out.println("Remove Complete Done");
            }
        });
        while (!done.get()) {
            Thread.sleep(500);
            System.out.println("Remove Node Sleeping");
        }

    } catch (Exception e) {
        System.out.println("Remove Node Exception: " + e.getMessage());
    }
}

我的输出如下：

in run() - about to removeNode https://<instance>.firebaseio.com/node/node
Start Remove Node: https://<instance>.firebaseio.com/node/node
Remove Node Sleeping
Remove Node Sleeping
Remove Node complete
Remove Complete Done
Remove Node Sleeping
in run() - RemoveNode leaving normally
pool-3-thread-1
All threads handled so far? {true}
Complete

Process finished with exit code 0

注意：我的结果与此类似。

ref.setValue(null, new Firebase.CompletionListener() {
            @Override
            public void onComplete(FirebaseError firebaseError, Firebase firebase) {
                done.set(true);
                System.out.println("setNull Node complete");
                if (firebaseError != null) {
                    System.out.println("ErrorCode: " + firebaseError.getCode());
                    System.out.println("ErrorMsg: " + firebaseError.getMessage());
                } else {
                    System.out.println("FirebaseError: NULL");
                }
                System.out.println("setNull Complete Done");
            }
        });

Answer 1

您用于删除的Firebase网址为https://BLAH/node/node

它应该是https://BLAH/node吗？

获取网址并将其粘贴到浏览器中，以便在Forge中查看，然后仔细检查数据是否存在。

Firebase Java API removeValue无效

1 个答案: