Question

我尝试在 MS Access 2010 中加入两个表，其中连接条件为ICD9 Code-Description。到目前为止，我还没弄清楚如何做到这一点。

我的两张表有这些关键栏目：

表1列842.00 - Sprain/strain, wrist *，其值如下：
924.11 - Contusion, knee
Dx
表2列842，其值如下：
924.11
FROM Table1 INNER JOIN Table2 ON Table1.Replace(LTrim(Replace(Left(ICD9Code-Description], (InStr(1,[ICD9Code-Description]," "))-1),"0"," "))," ","0") = Table2.Dx

我尝试过这两个加入条件：

SELECT ICD9
  FROM Table2 INNER JOIN 
       (SELECT Replace(LTrim(Replace(Left([ICD9 Code-Description],
              (InStr(1,[ICD9 Code-Description]," "))-1),"0"," "))," ","0") AS ICD9
          FROM Table1)
       ON Diag.DX = ICD9

和

Table1

这两种访问都不喜欢。

如果可能的话，我想避免在.getActive().getName();中将连接标准部分拉出到自己的列中。

这样做的Access方式是什么？

*不要讨厌我的列名。我没有创建它，我只需要支持它。

Answer 1

class GameViewController: UIViewController { func shuffle<C: MutableCollectionType where C.Index == Int>(var list: C) -> C { let c = count(list) for i in 0..<(c - 1) { let j = Int(arc4random_uniform(UInt32(c - i))) + i swap(&list[i], &list[j]) } return list } @IBOutlet weak var backround: UIImageView! @IBOutlet weak var button1: UIButton! @IBOutlet weak var button2: UIButton! @IBOutlet weak var button3: UIButton! @IBOutlet weak var button4: UIButton! @IBOutlet weak var button5: UIButton! @IBOutlet weak var Earthy: UIImageView! @IBOutlet weak var Blocker: UIImageView! @IBOutlet weak var asteroid5: UIImageView! @IBOutlet weak var asteroid4: UIImageView! @IBOutlet weak var asteroid3: UIImageView! @IBOutlet weak var asteroid2: UIImageView! @IBOutlet weak var asteroid1: UIImageView! let realAsteroid = UIImage(named: "Asteroid") var numberArray = ["1", "2", "3", "4", "5"] var playerScore = 0 var aliveOrNah:Bool = true var positioningNumRock = arc4random_uniform(5) + 1 var positioningNumBlocker = arc4random_uniform(5) + 1 //set random numbers override func viewDidLoad(){ var shuffledNumArray:Array = shuffle(numberArray) println(shuffledNumArray) var but1String:String = shuffledNumArray[0] var but2String:String = shuffledNumArray[1] var but3String:String = shuffledNumArray[2] var but4String:String = shuffledNumArray[3] var but5String:String = shuffledNumArray[4] self.button1.setTitle(but1String,forState: UIControlState.Normal) self.button2.setTitle(but2String,forState: UIControlState.Normal) self.button3.setTitle(but3String,forState: UIControlState.Normal) self.button4.setTitle(but4String,forState: UIControlState.Normal) self.button5.setTitle(but5String,forState: UIControlState.Normal) var posRandNum = arc4random_uniform(5) + 1 func offWithTheRocks(){ switch posRandNum{ case 1: self.asteroid1.center.y += view.bounds.height UIView.animateWithDuration(10.0, animations: { self.asteroid1.center.y -= self.view.bounds.height - 100 }) case 2: self.asteroid2.center.y += view.bounds.height UIView.animateWithDuration(10.0, animations: { self.asteroid2.center.y -= self.view.bounds.height - 100 }) case 3: self.asteroid3.center.y += view.bounds.height UIView.animateWithDuration(10.0, animations: { self.asteroid3.center.y -= self.view.bounds.height - 100 }) case 4: self.asteroid4.center.y += view.bounds.height UIView.animateWithDuration(10.0, animations: { self.asteroid4.center.y -= self.view.bounds.height - 100 }) case 5: self.asteroid5.center.y += view.bounds.height UIView.animateWithDuration(10.0, animations: { self.asteroid5.center.y -= self.view.bounds.height - 100 }) default: break } }函数＆＃34;将字符串中包含的数字作为相应类型的数值返回。＆＃34; （参见 Val函数

＆＃34;整洁的东西＆＃34;对于你的情况，它是从字符串中读取字符，直到它遇到一个不能成为有效数字一部分的字符。但它不会引发错误。它只保留已收集的数字字符并忽略其余部分。

这是“即时”窗口中的两个示例...

Val()

所以? Val("842.00 - Sprain/strain, wrist") 842 ? Val("924.11 - Contusion, knee") 924.11应该让你的Val()更加简单，即使你还需要在JOIN字符串上应用它......

Table2.Dx

Access中部分列的内部联接

1 个答案: