Question

我的Django型号上有以下字段：

ValidationError：[u＆＃34;＆＃39; 36.332＆＃39; value的格式无效。它必须是HH：MM [：ss [.uuuuuu]]格式。＆＃34;]

from django.db import models
class TestSuite(models.Model):

   time = models.TimeField()

当我解析我的.xml测试报告文件时，我有以下字段：

'time': u'36.332'

当我尝试通过**kwargs创建模型时，我发现以下错误：

  kwargs = {'time': u'36.332'}
  testsuite = TestSuite(**kwargs)

  Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 710, in save
    force_update=force_update, update_fields=update_fields)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 738, in save_base
    updated = self._save_table(raw, cls, force_insert, force_update, using, update_fields)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 822, in _save_table
    result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 861, in _do_insert
    using=using, raw=raw)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/manager.py", line 127, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 920, in _insert
    return query.get_compiler(using=using).execute_sql(return_id)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 970, in execute_sql
    for sql, params in self.as_sql():
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 928, in as_sql
    for obj in self.query.objs
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/__init__.py", line 710, in get_db_prep_save
    prepared=False)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/__init__.py", line 2293, in get_db_prep_value
    value = self.get_prep_value(value)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/__init__.py", line 2288, in get_prep_value
    return self.to_python(value)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/__init__.py", line 2275, in to_python
    params={'value': value},
ValidationError: [u"'36.332' value has an invalid format. It must be in HH:MM[:ss[.uuuuuu]] format."]

如何将字符串'time'转换为TimeField()对象？ *注意：* '36.332'表示36.332 seconds

Answer 1

TimeField字段不用于保存和/或表达一段时间，例如＆＃34; x秒＆＃34;，而是一天中的某个时间，例如说＆＃34; X事件发生在03：00：00＆＃34 ;;在这里，＆＃34; 03：00：00＆＃34;是TimeField的值。即你可能将其视为datetime.datetime对象的时间部分。

如果您需要存储的是金额时间，您可以使用任何其他符合您需求的内置字段（IntegerField，CharField等）并自行操作。

根据您需要的值，django-timedeltafield或DurationField也可能有用。虽然DurationField目前仅在django 1.8中可用。

我希望这有帮助！：）

将时间字符串转换为TimeField

1 个答案: