我试图对一组文档进行分组,并根据它们的值对它们进行计数。 例如
{ "_id" : 1, "item" : "abc1", "value" : "1" }
{ "_id" : 2, "item" : "abc1", "value" : "1" }
{ "_id" : 3, "item" : "abc1", "value" : "11" }
{ "_id" : 4, "item" : "abc1", "value" : "12" }
{ "_id" : 5, "item" : "xyz1", "value" : "2" }
在这里,我想分组" item"并获得一个计数"值"大于10且小了多少倍。所以:
{ "item": "abc1", "countSmaller": 2, "countBigger": 1}
{ "item": "xyz1", "countSmaller": 1, "countBigger": 0}
使用$ aggregate可以轻松实现普通计数,但我怎样才能达到上述结果?
答案 0 :(得分:9)
您需要的是聚合框架的$cond
运算符。获得你想要的东西的一种方法是:
db.foo.aggregate([
{
$project: {
item: 1,
lessThan10: { // Set to 1 if value < 10
$cond: [ { $lt: ["$value", 10 ] }, 1, 0]
},
moreThan10: { // Set to 1 if value > 10
$cond: [ { $gt: [ "$value", 10 ] }, 1, 0]
}
}
},
{
$group: {
_id: "$item",
countSmaller: { $sum: "$lessThan10" },
countBigger: { $sum: "$moreThan10" }
}
}
])
注意:我假设value
为数字而不是字符串。
<强>输出:强>
{
"result" : [
{
"_id" : "xyz1",
"countSmaller" : 1,
"countBigger" : 0
},
{
"_id" : "abc1",
"countSmaller" : 2,
"countBigger" : 2
}
],
"ok" : 1
}
答案 1 :(得分:0)
如果有人正在寻找这种情况的Java代码(根据我的需要更新了字段):
Aggregation aggregation = Aggregation.newAggregation(
Aggregation.project("environment").and("success").applyCondition(ConditionalOperators.when(Criteria.where("deploymentStatus").is("SUCCESS"))
.then(1)
.otherwise(0)).and("failed").applyCondition(ConditionalOperators.when(Criteria.where("deploymentStatus").is("FAILURE"))
.then(1)
.otherwise(0)),
Aggregation.group("environment").sum("success").as("success").sum("failed").as("failed"));