Question

我正在使用SQL Oracle，我想使用MAX函数而不是ROWNUM更改我的查询。

SELECT * 
FROM (SELECT a.name, price.price
FROM price
LEFT JOIN a 
ON a.id = price.tk_a
ORDER BY price.price DESC)
WHERE ROWNUM <=1;

请提供任何帮助或建议？

Answer 1

您可以将MAX聚合函数与KEEP ( DENSE_RANK FIRST ORDER BY ... )一起使用，以获得另一列的最大值：

SELECT MAX( a.name ) KEEP ( DENSE_RANK FIRST ORDER BY p.price DESC ) AS name,
       MAX( p.price ) AS price
FROM   a
       LEFT OUTER JOIN price p
       ON ( a.id = p.tk_a );

Answer 2

MAX和分组

SELECT a.name, MAX(p.price)
FROM price
LEFT JOIN a ON a.id = p.tk_a
GROUP BY a.name
ORDER BY p.price DESC

如果您只想要单个MAX价格，请使用此

SELECT MAX(p.price), (SELECT MAX(b.name) FROM a b LEFT JOIN price pp ON b.id = pp.tk_a WHERE a.id = b.id AND p.price = pp.price) AS name
FROM price
LEFT JOIN a ON a.id = p.tk_a
ORDER BY p.price DESC

Answer 3

试试这个：

select a1.name, p1.price
from price p1
JOIN a a1 ON a1.id = p1.tk_a
JOIN (SELECT MAX(p.price)
      FROM price p) C on p1.price = c.price

Answer 4

使用此

SELECT * 
FROM (SELECT a.name,MAX( price.price)
FROM price
LEFT JOIN a 
ON a.id = price.tk_a
GROUP BY a.name 
ORDER BY price.price DESC)

使用MAX（）函数获得最大的价格

4 个答案: