我正在尝试根据数组中某个参数的值过滤对象数组。但是，当我尝试做同样的事情时，会抛出错误＆＃34;参数＆＃39; [value]不是函数，未定义。
$ scope.model.selection将包含基于用户选择的数组值（比如复选框）
$scope.model.selection = ["m1", "m2"]
我编写了代码，只从json中获取_source值作为对象。现在我只想要通过特定条件的对象，即[＆＃34; m1＆＃34;]
中的机器名我的代码：
var filter;
filter = sourcearray.filter(function (filterinstance)
{
return filterinstance.machinename in $scope.model.selection;
});
我的数据：
{
"kal": [
{
"_index": "log2015.18",
"_type": "MT_DETAIL",
"_sc": null,
"_source": {
"value1": 0,
"value2": "2",
"value3": "MON",
"machine": "m1"
},
"sort": [
1
]
},
{
"_index": "logw-2015.18",
"_type": "MT_DETAIL",
"_sc": null,
"_source": {
"value1": 1,
"value2": "3",
"value3": "MON1",
"machine": "m1"
},
"sort": [
2
]
},
{
"_index": "log-2015.18",
"_type": "MT_DETAIL",
"_sc": null,
"_source": {
"value1": 3,
"value2": "265",
"value3": "MON2",
"machine": "m2"
},
"sort": [
3
]
},
{
"_index": "log2015.18",
"_type": "MT_DETAIL",
"_sc": null,
"_source": {
"value1": 4,
"value2": "5",
"value3": "MON5",
"machine": "m2"
},
"sort": [
1
]
},
{
"_index": "log2015.18",
"_type": "MT_DETAIL",
"_sc": null,
"_source": {
"value1": 7,
"value2": "3",
"value3": "MON8"
},
"sort": [
1
]
}
]
}