我正在尝试解决这个问题:https://www.hackerrank.com/challenges/morgan-and-a-string
这是我的代码:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int t = Integer.parseInt(sc.nextLine());
while((t--)>0)
{
String s1 = sc.nextLine();
String s2 = sc.nextLine();
System.out.println(ms(s1,s2));
}
}
public static String ms(String s1, String s2)
{
StringBuffer sb = new StringBuffer();
int i,j;
for(i=0,j=0;i<s1.length() || j<s2.length() ;)
{
if(s1.charAt(i)>s2.charAt(j))
{
sb.append(s2.charAt(j));
if(j==s2.length())
break;
else
j++;
}
else
{
sb.append(s1.charAt(i));
if(i==s1.length())
break;
else
i++;
}
}
if(j==s2.length())
{
for(;i<s1.length();i++)
sb.append(s1.charAt(i));
return sb.toString();
}
else
{
for(;j<s2.length();j++)
sb.append(s2.charAt(j));
return sb.toString();
}
}
}
我收到此错误:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 4
at java.lang.String.charAt(String.java:658)
at Solution.ms(Solution.java:28)
at Solution.main(Solution.java:18)
有谁能告诉我哪里出错了?我无法找到错误...
答案 0 :(得分:3)
我不知道您正在尝试使用该程序,但我认为这将消除您的错误
for(i=0,j=0;i<s1.length() & j<s2.length() ;)
答案 1 :(得分:2)
我刚刚更改了你的for循环,如下所示,我可以毫无问题地执行程序
for(i = 0, j = 0; i < s1.length() && j < s2.length();)
PFB源代码
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t = Integer.parseInt(sc.nextLine());
while ((t--) > 0) {
String s1 = sc.nextLine();
String s2 = sc.nextLine();
System.out.println(ms(s1, s2));
}
}
public static String ms(String s1, String s2) {
StringBuffer sb = new StringBuffer();
int i, j;
for (i = 0, j = 0; i < s1.length() && j < s2.length();) {
if (s1.charAt(i) > s2.charAt(j)) {
sb.append(s2.charAt(j));
if (j == s2.length())
break;
else
j++;
} else {
sb.append(s1.charAt(i));
if (i == s1.length())
break;
else
i++;
}
}
if (j == s2.length()) {
for (; i < s1.length(); i++)
sb.append(s1.charAt(i));
return sb.toString();
}
else {
for (; j < s2.length(); j++)
sb.append(s2.charAt(j));
return sb.toString();
}
}
}