Question

我尝试实现车辆部件产品过滤，其中products属于许多不同的fitments。比如特定的灯泡可以属于雪佛兰，福特和本田汽车。

我遇到的问题是使用AND而OR只是不能正常工作。

以下是我要查找的结果的伪代码（表格结构和数据位于底部）：

SELECT * FROM products
JOIN fitments ON fitments.sku = products.sku

WHERE ANY fitments.make (grouped by sku) MATCHES ALL 'Ford' AND 'Chevrolet' AND 'Honda'

AND products.active = 1
AND fitments.cat_name = 'Cars'
GROUP BY products.sku

福特，雪佛兰和本田并不存在于同一行，所以我不能把它变成一个WHERE子句？

OR无法正常工作，因为我不想返回不符合所有条件的结果。

AND不起作用，因为不是每一行都包含所有三个makes并且会返回0行。

我试图实现的结果：

我需要帮助的查询结果会返回一行products行（不是fitments，因为fitments只是关系查找），BULB2因为匹配所有可能的装备中有三个make参数（福特，雪佛兰和本田）。

两个表，产品和配件：

CREATE TABLE `fitments` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `cat_name` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
  `sku` varchar(14) COLLATE utf8_unicode_ci DEFAULT NULL,
  `make` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
  `model` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
  `start_year` varchar(4) COLLATE utf8_unicode_ci DEFAULT NULL,
  `end_year` varchar(4) COLLATE utf8_unicode_ci DEFAULT NULL,
  `created_at` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  `updated_at` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=30211 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

CREATE TABLE `products` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `sku` varchar(14) COLLATE utf8_unicode_ci DEFAULT NULL,
  `name` varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL,
  `active` tinyint(1) NOT NULL,
  `created_at` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  `updated_at` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=63730 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('1', 'Cars', 'BULB1', 'Ford', 'F150', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('2', 'Cars', 'BULB2', 'Ford', 'Explorer', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('3', 'Cars', 'BULB1', 'Ford', 'Mustang', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('4', 'Cars', 'BULB2', 'Chevrolet', 'Cobalt', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('5', 'Cars', 'BULB3', 'Chevrolet', 'Corvette', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `fitments` (`id`, `cat_name`, `sku`, `make`, `model`, `start_year`, `end_year`, `created_at`, `updated_at`) VALUES ('6', 'Cars', 'BULB2', 'Honda', 'Civic', '2013', '2015', '0000-00-00 00:00:00', '0000-00-00 00:00:00');


INSERT INTO `products` (`id`, `sku`, `name`, `active`, `created_at`, `updated_at`) VALUES ('1', 'BULB1', 'Generic Bulb 1', '1', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `products` (`id`, `sku`, `name`, `active`, `created_at`, `updated_at`) VALUES ('2', 'BULB2', 'Generic Bulb 2', '1', '0000-00-00 00:00:00', '0000-00-00 00:00:00');
INSERT INTO `products` (`id`, `sku`, `name`, `active`, `created_at`, `updated_at`) VALUES ('3', 'BULB3', 'Generic Bulb 3', '1', '0000-00-00 00:00:00', '0000-00-00 00:00:00');

Answer 1

SELECT sku
  FROM fitments 
 WHERE make IN('Ford', 'Chevrolet', 'Honda') 
 GROUP 
    BY sku HAVING COUNT(DISTINCT make) = 3;

Answer 2

答案很容易，如果你改写一下你的问题：不要说＆＃34;加入福特和雪佛兰和本田＆＃34;而只是说＆＃34;加入福特并加入雪佛兰AND加入本田＆＃34;：

SELECT
  products.*
  -- , whatever.column you need else
FROM
  products
  INNER JOIN fitments AS fitmentsFord ON products.sku=fitmentsFord.sku
  INNER JOIN fitments AS fitmentsChevrolet ON products.sku=fitmentsChevrolet.sku
  INNER JOIN fitments AS fitmentsHonda ON products.sku=fitmentsHonda.sku
WHERE
  fitmentsFord.make='Ford'
  AND fitmentsChevrolet.make='Chevrolet'
  AND fitmentsHonda.make='Honda'
  AND products.active = 1
  AND fitments.cat_name = 'Cars'
GROUP BY products.sku

Answer 3

试试这个::

SELECT p.sku FROM products p
INNER JOIN 
(Select * from fitments group by make, sku) f ON f.sku = p.sku 
group by p.sku  having count(f.make)=3

MySQL SELECT车辆装配选择和过滤

3 个答案: