因为它是MyClass x = 120;
,是否可以创建这样的自定义类?
如果是这样,我该怎么做?
答案 0 :(得分:4)
不确定这是否是您想要的,但您可以通过实现隐式运算符来实现: http://msdn.microsoft.com/en-us/library/z5z9kes2(VS.71).aspx
答案 1 :(得分:4)
使用隐式运算符通常被认为是一个坏主意,因为它们毕竟是隐含的并且在您的背后运行。调试代码乱丢运算符重载是一场噩梦。也就是说,有这样的事情:
public class Complex
{
public int Real { get; set; }
public int Imaginary { get; set; }
public static implicit operator Complex(int value)
{
Complex x = new Complex();
x.Real = value;
return x;
}
}
你可以使用:
Complex complex = 10;
或者你可以重载+运算符
public static Complex operator +(Complex cmp, int value)
{
Complex x = new Complex();
x.Real = cmp.Real + value;
x.Imaginary = cmp.Imaginary;
return x;
}
并使用像
这样的代码complex +=5;
答案 2 :(得分:3)
创建一个隐式运算符:
http://msdn.microsoft.com/en-us/library/z5z9kes2.aspx
例如:
public struct MyStruct // I assume this is what you meant, since you mention struct in your title, but use MyClass in your example.
{
public MyClass(int i) { val = i; }
public int val;
// ...other members
// User-defined conversion from MyStruct to double
public static implicit operator int(MyStruct i)
{
return i.val;
}
// User-defined conversion from double to Digit
public static implicit operator MyStruct(int i)
{
return new MyStruct(i);
}
}
“这是个好主意吗?”值得商榷。隐式转换往往会破坏程序员的公认标准;一般不是一个好主意。但是,如果你正在做一些大型价值库,那么它可能是一个好主意。
答案 3 :(得分:1)
public struct MyCustomInteger
{
private int val;
private bool isDef;
public bool HasValue { get { return isDef; } }
public int Value { return val; } }
private MyCustomInteger() { }
private MyCustomInteger(int intVal)
{ val = intVal; isDef = true; }
public static MyCustomInteger Make(int intVal)
{ return new MyCustomInteger(intVal); }
public static NullInt = new MyCustomInteger();
public static explicit operator int (MyCustomInteger val)
{
if (!HasValue) throw new ArgumentNullEception();
return Value;
}
public static implicit operator MyCustomInteger (int val)
{ return new MyCustomInteger(val); }
}