我正在尝试将数据保存到android中的文件中,而我似乎无法发现我的错误,我正在努力阅读它。
概述: 我有2个按钮和editext
我在编辑文本中输入内容,然后按"保存"按钮保存到文件(save_to_file函数)。 当我按下"阅读"按钮(read_file函数)我得到类似B [] @ 3213的东西 我按照here
的android教程进行了操作我的代码:
package com.keddy.filetesting;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.EditText;
import java.io.FileInputStream;
import java.io.FileOutputStream;
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
public void save_to_file(View view){
try{
String filename = "Myfile.txt";
EditText buffer= (EditText)findViewById(R.id.editText);
String pureText= buffer.getText().toString();
pureText += '\n';
FileOutputStream fos = openFileOutput(filename , Context.MODE_APPEND);
fos.write(pureText.getBytes());
fos.close();
}catch(Exception e){
e.printStackTrace();
}
}
public void read_file(View view){
try
{
String filename = "Myfile.txt";
FileInputStream fis = openFileInput(filename);
int len = fis.read();
byte[] buff = new byte[len];
fis.read(buff,0,len);
EditText changeText = (EditText)findViewById(R.id.editText);
changeText.setText(buff.toString());
}catch(Exception e){
e.printStackTrace();
}
}
}
我似乎无法发现自己的错误,因为我非常仔细地阅读了教程,可能是我的问题在于阅读吗?
答案 0 :(得分:2)
读取没有问题 - 你只是调用缓冲区对象本身的toString()方法。这不会输出其内容,而是输出内存地址。
尝试致电:
changeText.setText(new String(buff));
此外,在转换过程中考虑底层字符集(请参阅String-Doc)。如果您的文件很大,请不要立即读取缓冲区并使用StringBuilder连接读数。
答案 1 :(得分:0)
public void save_to_file() throws Exception
{
FileOutputStream fos = null;
try
{
String filename = "Myfile.txt";
EditText buffer= (EditText)findViewById(R.id.editText);
String pureText= buffer.getText().toString()
pureText += "\n"; // double-quote
FileOutputStream fos = openFileOutput(filename , Context.MODE_APPEND);
fos.write(pureText);
// call 'flush' and 'close' in the finally clause
}
catch(Exception e)
{
throw e;
//e.printStackTrace();
}
finally
{
if(fos != null)
{
try
{
fos.flush();
}
catch(Exception e)
{
throw e;
}
finally
{
try
{
fos.close();
}
catch(Exception e)
{
throw e;
}
}
}
}
}
public void read_file() throws Exception
{
FileReader fileReader = null;
try
{
String filename = "Myfile.txt";
fileReader = new FileReader( openFileInput(filename) );
StringWriter stringWriter = new StringWriter();
int len = -1;
char[] buff = new char[512];
while((len = fix.read(buff)) != -1)
stringWriter.write(buff,0,len);
String fileContents = stringWriter.toString();
EditText changeText = (EditText)findViewById(R.id.editText);
changeText.setText(fileContents);
}
catch(Exception e)
{
throw e;
//e.printStackTrace();
}
finally
{
if(fileReader != null)
{
try
{
fileReader.close();
}
catch(Exception e)
{
throw e
}
}
}
}