Question

我创建了多个模型

public class Room
    {
        public int Id { get; set; }
        public string NumberRoom { get; set; }
        public virtual ICollection<Photo> Photo { get; set; }
    }
public class Photo
    {
        public int Id { get; set; }
        public string PhotoName { get; set; }
        public int Roomid { get; set; }
        public virtual Room Room { get; set; }
    }

有两种不同的型号：

Submit

在点击DropDownListFor在我的视图我想要上传图像的文件夹与来自DropDownListFor所选项目的名称（例如/图像/ 2 /，其中2 =从ID为@using Hotel.BusinessObject @model MultipleModel @using (Html.BeginForm("AddRoomImg", "Admin", FormMethod.Post, new { enctype = "multipart/form-data", id = Model.Room.Id})) { <div>@Html.DropDownListFor(m=> m.Room.Id, ViewBag.roomlist as SelectList, "Select Room")</div> <input type="file" name="img" /> <input type="submit" value="upload" /> }），并添加到数据库。我怎样才能使用Html.BeginForm从DropDownListFor正确发送所选项目？我的观点：

Room.Id

我的控制器formCollection中的int? id总是= 0且NULL不起作用并返回public ActionResult AddRoomImg() { ViewBag.roomlist = new SelectList(db.Room, "Id", "NumberRoom"); return View(); } [HttpPost] public ActionResult AddRoomImg(FormCollection formCollection, int? id) { foreach (string item in Request.Files) { HttpPostedFileBase file = Request.Files[item] as HttpPostedFileBase; if (file.ContentLength == 0) continue; if (file.ContentLength > 0) { ImageUpload imageUpload = new ImageUpload { Width = 600 }; ImageResult imageResult = imageUpload.RenameUploadFile(file); if (imageResult.Success) { //TODO: write the filename to the db } else { ViewBag.Error = imageResult.ErrorMessage; } } }

typedef void *HIMAGE;  // Image Handle
HIMAGE LoadImage(...);

Answer 1

试试这个

[HttpPost]
public ActionResult AddRoomImg(MultipleModel model, HttpPostedFileBase img)
{
     //your code here
}

或

[HttpPost]
public ActionResult AddRoomImg(MultipleModel model)
{
     var image = Request.Files(0); //access your images

     //rest of your code here
}

获取DropDownListFor多个模型中的选定值

1 个答案: