Question

我认识我，我的问题听起来很愚蠢，因为网上有很多答案。我已经创建了一个用于登录和注册的html页面。我被要求使用xampp来托管我的网页。我创建了一个数据库和表，并在xampp的sql中插入数据。但是当我提供lognin和注册详细信息并提交时，该页面会抛出各种异常。我在这里发布此内容的主要原因是，这是我的最终项目在3天内完成截止日期，如果我不做这项简单的工作，我就不会被评分。我尝试了很多，但我一直在收到错误。所以我需要一些快速的帮助。我需要一个使用连接到数据库的php登录页面。你的一点帮助可以让我免于得到F，我真的很感激。

Answer 1

数据库结构

CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `username` varchar(255) NOT NULL,
  `password` varchar(255) NOT NULL,
  `first_name` varchar(255) NOT NULL,
  `last_name` varchar(255) NOT NULL,
  `email` varchar(255) NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `username` (`username`),
  UNIQUE KEY `email` (`email`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

如果你使用mysql使用phpmyadmin来创建这些字段会更容易

现在我已经定义了连接数据库所需的常量创建一个文件dbConstants.php或者将其命名为

现在，登录页面的代码创建了一个名为register.php的文件

<html>
<head>
    <title>Login Form</title>
</head>
<body>

<?php

if (!isset($_POST['submit'])){
?>
<!-- The HTML login form -->
    <form action="<?=$_SERVER['PHP_SELF']?>" method="post">
        Username: <input type="text" name="username" /><br />
        Password: <input type="password" name="password" /><br />

        <input type="submit" name="submit" value="Login" />
    </form>

<?php
} else {
    require_once("db_const.php");
    $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
    # check connection
    if ($mysqli->connect_errno) {
        echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
        exit();
    }

    $username = $_POST['username'];
    $password = $_POST['password'];

    $sql = "SELECT * from users WHERE username LIKE '{$username}' AND password LIKE '{$password}' LIMIT 1";
    $result = $mysqli->query($sql);
    if (!$result->num_rows == 1) {
        echo "<p>Invalid username/password combination</p>";
    } else {
        echo "<p>Logged in successfully</p>";
        // do stuffs
    }
}
?>      
</body>
</html>

最后注册代码创建了一个名为register.php的文件

<html>
<head>
    <title>Registration</title>
</head>
<body>  
<?php
require_once("db_const.php");
if (!isset($_POST['submit'])) {
?>  <!-- The HTML registration form -->
    <form action="<?=$_SERVER['PHP_SELF']?>" method="post">
        Username: <input type="text" name="username" /><br />
        Password: <input type="password" name="password" /><br />
        First name: <input type="text" name="first_name" /><br />
        Last name: <input type="text" name="last_name" /><br />
        Email: <input type="type" name="email" /><br />

        <input type="submit" name="submit" value="Register" />
    </form>
<?php
} else {
## connect mysql server
    $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
    # check connection
    if ($mysqli->connect_errno) {
        echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
        exit();
    }
## query database
    # prepare data for insertion
    $username   = $_POST['username'];
    $password   = $_POST['password'];
    $first_name = $_POST['first_name'];
    $last_name  = $_POST['last_name'];
    $email      = $_POST['email'];

    # check if username and email exist else insert
    $exists = 0;
    $result = $mysqli->query("SELECT username from users WHERE username = '{$username}' LIMIT 1");
    if ($result->num_rows == 1) {
        $exists = 1;
        $result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
        if ($result->num_rows == 1) $exists = 2;    
    } else {
        $result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
        if ($result->num_rows == 1) $exists = 3;
    }

    if ($exists == 1) echo "<p>Username already exists!</p>";
    else if ($exists == 2) echo "<p>Username and Email already exists!</p>";
    else if ($exists == 3) echo "<p>Email already exists!</p>";
    else {
        # insert data into mysql database
        $sql = "INSERT  INTO `users` (`id`, `username`, `password`, `first_name`, `last_name`, `email`) 
                VALUES (NULL, '{$username}', '{$password}', '{$first_name}', '{$last_name}', '{$email}')";

        if ($mysqli->query($sql)) {
            //echo "New Record has id ".$mysqli->insert_id;
            echo "<p>Registred successfully!</p>";
        } else {
            echo "<p>MySQL error no {$mysqli->errno} : {$mysqli->error}</p>";
            exit();
        }
    }
}
?>      
</body>
</html>

这是一个简单的登录和注册过程我希望它可以帮助你，虽然我在这里给出的东西可能不是最好的做法，至少会帮助你使用mysqli更好地使用pdo。

如何使用php和xampp

1 个答案: