如何在Xamarin中发送HTTP POST请求?

时间:2015-05-10 09:59:51

标签: c# rest xamarin webclient

我这里有一个远程地址: http://damp-sands-2243.herokuapp.com/students

我需要通过API调用插入新学生。

以下是我使用javasript的方式:

var data  = {"name":"Meg",
"regi_number":38};

$(document).ready(function(){
    $.ajax({
            type: "POST",
            url: "/students/",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            data: JSON.stringify(data),
            success: function(){console.log("boo");}
          });
 });

您可以访问该网址并使用浏览器的javascript控制台检查其是否有效。

现在,我的问题是从Xamarin做同样的事情。 这是我做的,

try{
 string data = "{\"name\":\"Meg\",\"regi_number\":38}";
        WebClient client = new WebClient();
        client.Encoding = System.Text.Encoding.UTF8;
        string reply = client.UploadString("https://damp-sands-2243.herokuapp.com/students/", data);
        // Disply the server's response.
        Console.WriteLine(reply);
}

catch(Exception ex){
       Console.Out.WriteLine("Debug has been started");
       Console.Out.WriteLine(ex.GetType().FullName);
       Console.Out.WriteLine(ex.GetBaseException().ToString());
}

现在我收到以下错误:

  

05-10 15:48:11.644 I / mono-stdout(32078):已启动调试       System.Net.WebException       05-10 15:48:11.645 I / mono-stdout(32078):System.Net.WebException       System.Net.WebException:远程服务器返回错误:(422)Unprocessable Entity。       05-10 15:48:11.658 I / mono-stdout(32078):System.Net.WebException:远程服务器返回错误:(422)Unprocessable Entity。         在System.Net.HttpWebRequest.CheckFinalStatus(System.Net.WebAsyncResult result)[0x0033b] in:0         在System.Net.HttpWebRequest.SetResponseData(System.Net.WebConnectionData data)[0x00165] in:0

1 个答案:

答案 0 :(得分:4)

所以错误非常简单。如果您访问该页面并在控制台中执行javascript代码,则会收到以下请求

POST http://damp-sands-2243.herokuapp.com/students/ HTTP/1.1
Host: damp-sands-2243.herokuapp.com
User-Agent: Mozilla/5.0 (Windows NT 6.3; WOW64; rv:37.0) Gecko/20100101 Firefox/37.0
Accept: application/json, text/javascript, */*; q=0.01
Accept-Language: de,en-US;q=0.7,en;q=0.3
Accept-Encoding: gzip, deflate
X-CSRF-Token: jCQqRuqRk4gEK4+rgybQu2+isCvWXI3oZiWsPyrmHF8mportbRS/pBm761rDrQpDv3TI3JICnE40xK59HQCBOA==
Content-Type: application/json; charset=utf-8
X-Requested-With: XMLHttpRequest
Referer: http://damp-sands-2243.herokuapp.com/students
Content-Length: 31
Cookie: _restest_session=Yi82UXBXeTdmMjFiT0Rud2tNQTlvRUhxZ0VWRndHeUc4TWZLY3M2ejFtcXorTEw1cWIwb1lNRXdUZDlHWnp2bHpuTlVxL1BYdGg2ckNVM0JDWHZZSUJTS3BWU3BRY0diY3NBSUNBQ0l0MEVLYzZCQjB5Z2syK3pmVUFrazQ3UlhsU1B5OGc0cXk4SzkrY0c5VHdoTkc3RnoxSTIvUWswN3ZrQk5QK1pNNVExcG9Bak1qczV4azRtbVpKaTEzRDgyQkoycGlsdy9qanZLem9RazhEelpqT0dnTXdZZldNS3NXcHhnbC8vd1haaW04NXNGUlpSMVlvT0dGeFQvYWlBSzR5SlFyd3RZN2NIQnNBNDYzYUU0ckE9PS0ta1BPN1ZwczJ1bGE2VnhJT0ZWcUhxUT09--2e9406ef247f597812cd2278422527eb2b679e87; request_method=POST
Connection: keep-alive
Pragma: no-cache
Cache-Control: no-cache

{"name":"Meg","regi_number":38}

如您所见,请求包含cookie和CSRF-Token。如果您不将它们添加到请求中,则会出现您所面临的422错误。

所以,首先你必须向页面发出请求,获取cookie和csrfToken:

WebClient wc = new WebClient();
string baseSiteString = wc.DownloadString("http://damp-sands-2243.herokuapp.com/students");
string csrfToken = Regex.Match(baseSiteString, "<meta name=\"csrf-token\" content=\"(.*?)\" />").Groups[1].Value;
string cookie = wc.ResponseHeaders[HttpResponseHeader.SetCookie];
Console.WriteLine("Token: {0}", csrfToken);
Console.WriteLine("Cookie: {0}", cookie);

下一部分是使用所有重要标题发出请求:

wc.Headers.Add(HttpRequestHeader.Cookie, cookie);
wc.Headers.Add(HttpRequestHeader.ContentType, "application/json; charset=utf-8");
wc.Headers.Add(HttpRequestHeader.Accept, "application/json, text/javascript, */*; q=0.01");
wc.Headers.Add("X-CSRF-Token", csrfToken);
wc.Headers.Add("X-Requested-With", "XMLHttpRequest");

string dataString = @"{""name"":""Meg"",""regi_number"":38}";
byte[] dataBytes = Encoding.UTF8.GetBytes(dataString);
byte[] responseBytes = wc.UploadData(new Uri("https://damp-sands-2243.herokuapp.com/students/"), "POST", dataBytes);
string responseString = Encoding.UTF8.GetString(responseBytes);
Console.WriteLine(responseString);

那就是:)