Question

我试图在我的debian7 bash中生成许多无效的ipv4地址和一些有效的地址。我的计划是：

echo {0..3 , 00..03 , 000..003 , 300..303 , 254..257 ,  0254..0257 , fail , 888}
echo -e "\n"!^.!^.!^.!^ >> ip.txt

但它只是回应

"{0..3 00..03 000..003 300..303 254..257 0254..0257 fail 888}" x4

每当我为每个花括号提供多个数字区域时。

echo {a..c , A..C} end up as
"{a..c A..C}" 

where i want 

"a b c A B C"

所以我很好奇，如果甚至可以使用＆gt;＆gt;只有一个大括号＆lt;＆lt;

__

我的下一个想法是像这样解决它：

echo -e "\n"{0..3}.{0..3}.{0..3}.{0..3} >> ip.txt
^0..3^00..03

but there is only replaces one piece

echo -e "\n"{00..03}.{0..3}.{0..3}.{0..3} >> ip.txt

有没有办法使用这个“^ x ^ y”工具一次性替换所有？

抱歉这个基本问题我刚刚进入bash并想在家里学习除了学校课程

感谢任何有关必要文献的帮助或提示

Answer 1

我猜你想要这样的事情：

for a in {{0..3},{00..03},{000..003},{300..303},{254..257},{0254..0257},fail,888} ; do
    for b in {{0..3},{00..03},{000..003},{300..303},{254..257},{0254..0257},fail,888} ; do
        for c in {{0..3},{00..03},{000..003},{300..303},{254..257},{0254..0257},fail,888} ; do
            for d in {{0..3},{00..03},{000..003},{300..303},{254..257},{0254..0257},fail,888} ; do
                echo "$a"."$b"."$c"."$d"
            done
        done
    done
done

脚本输出456976想要的IP地址：

0.0.0.0
0.0.0.1
0.0.0.2
0.0.0.3
0.0.0.00

...

888.888.888.0255
888.888.888.0256
888.888.888.0257
888.888.888.fail
888.888.888.888

如果你想避免使用循环，你可以用.这样连接每个部分：

echo -e {{1..3},{5..7}}.{{1..3},{5..7}}.{{1..3},{5..7}}.{{1..3},{5..7}}"\n"

基本bash脚本，枚举和comman替换工具问题

1 个答案: