Question

我正在编写一个程序来打印字母和（一，二，三个字母等）单词的出现。到目前为止，我已经让字母部分正常工作，但我无法将该部分用于工作，更不用说区分一个，两个或三个字母单词。我试图找出程序搞乱的地方，而且似乎是我试图将它们存储在数组中＆＃34; word＆＃34;。

有人建议使用strlok（），但没有提到。

编辑：我用sizeof（）替换了strlen（）并设置了我的＆＃39; i＆＃39;变量= 0应该是，但我的输出仍然是整个字符串的第一个字母和一些奇怪的字符。

#include <stdio.h>
#include <string.h>
#include <ctype.h>
void findLetters(char *ptr);
void findWords(char *point);


int main()
{
    char textStream[100]; //up to 98 characters and '\n\ and '\0'

    printf ( "enter some text\n");
    if ( fgets( textStream, sizeof ( textStream), stdin)) //input up to 99 characters
    {
        findLetters(textStream);
    }
    else
    {
        printf ( "fgets failed\n");
    }
    findWords(textStream);
    return 0;
}

void findLetters(char *ptr) //find occurences of all letters
{
    int upLetters[26];
    int loLetters[26];
    int i;
    int index;

    for ( i = 0; i < 26; i++) // set array to all zero
    {
        upLetters[i] = 0;
        loLetters[i] = 0;
    }
    i = 0;
    while ( ptr[i] != '\0') // loop until prt[i] is '\0'
    {
        if (ptr[i] >= 'A' && ptr[i] <= 'Z') //stores occurrences of uppercase letters
        {
            index = ptr[i] - 'A';// subtract 'A' to get index 0-25
            upLetters[index]++;//add one
        }

        if (ptr[i] >= 'a' && ptr[i] <= 'z') //stores occurrences of lowercase letters
        {
            index = ptr[i] - 'a';//subtract 'a' to get index 0-25
            loLetters[index]++;//add one
        }
        i++;//next character in ptr
    }
    printf("Number of Occurrences of Uppercase letters\n\n");
    for ( i = 0; i < 26; i++)//loop through 0 to 25
    {
        if ( upLetters[i] > 0)
        {
            printf("%c : \t%d\n", (char)(i + 'A'), upLetters[i]);
            // add 'A' to go from an index back to a character
        }
    }
    printf("\n");
    printf("Number of Occurrences of Lowercase letters\n\n");
    for ( i = 0; i < 26; i++)
    {
        if ( loLetters[i] > 0)
        {
            printf("%c : \t%d\n", (char)(i + 'a'), loLetters[i]);
            // add 'a' to go back from an index to a character
        }
    }
}

void findWords(char *point)
{
    int i = 0; 
    int k = 0; 
    int count = 0;
    int j = 0; 
    int space = 0;
    int c = 0;
    char word[50][100], word1[50][100];

    for (;i < sizeof(point);i++) //counts # of spaces between words
    {
        if ((point[i] == ' ')||(point[i] == ',')||(point[i] == '.'))
        {
            space++;
        }
    }
    i = 0; 
    for(; i < sizeof(point); i++) //seperates strings from each other
    {
        if(point[i] == '.' || point[i] == 44|| point[i] == 46)
        {
            word[j][k] = '\0';
            j++;
            k = 0;
            printf("%s\n",point[i]);
        }
        else
        {
            word[j][k] = point[i];
            k++;
        }
        printf("%s\n",word[j]);
    }
    k = 0;

    for (i = 0;i <= space;i++) 
    {
        for (j = 0;j <= space;j++) 
        {
            if (i == j) // finds occurrences of words
            {
                strcpy(word1[k], word[i]); //copies words in new array
                k++;
                count++;

            } 
            else if(strcmp(word1[j], word[i]) != 0) //makes sure that the word copied equals the word from the string
            {
                ;
            }
        }
    }
    j = 0;
    i = 0;
    for (;i < count ;i++) 
    {
        for (;j <= space;j++)
        {
            if (strcmp(word1[i], word[j]) == 0) //counts occurrence of each word
            {
                c++;
            }
        }
        printf("%s \t %d times\n", word1[i], c);
        c = 0;
    }
}

Answer 1

您的代码中存在一些问题：

for(;i < strlen(point); i++) //seperates strings from each other执行此行时，i的值已经为strlen，因此未执行以下for。添加i=0进行修复。
你应该使用sizeof而不是strlen，否则你会错过最后一个单词。
if(point[i] == '.' || point[i] == 44|| point[i] == 46)您未在此处检查' '。正确的if条件应该是： if(point[i] == ' ' || point[i] == '.'|| point[i] == ' ')
您的代码没有考虑到您有逗号和空格的情况。
您用于在数组中查找单词的算法存在缺陷。你应该使用这样的东西：

how_many_times(word[i], word, number_of_words);

int how_many_times(char * word, char words[50][100], int how_many_words) {
  int i = 0, counter=0;                                                                         
  for (i=0; i< how_many_words; i++) {
    if ( strcmp(words[i], word) == 0 ) {
      counter++;
    }
  } 
  return counter;
}

Answer 2

一个主要问题是你的第二个循环没有运行：

    int i=0;
    for (;i < strlen(point);i++) //counts # of spaces between words
    {
      ...
    }

    for(;i < strlen(point); i++) //seperates strings from each other
    {
      ...
    }

i在第二个strlen(point)-1循环开始时仍为for，因此无法运行。我建议始终在for循环中指定起始点，并且还只计算一次字符串长度，而不是每个循环。

int len = strlen(point);
for (i=0; i < len; i++)

为什么我会得到如此混乱的输出？

2 个答案: