Question

我需要在表单中设置一个单选按钮;必须使用来自AJAX响应的值检查它。

我的AJAX响应为response.drive。＆＃34;手动＆＃34;或者＆＃34; Auto＆＃34;可能是它的价值。

更新所以我尝试了一些不同的方法，但我无法解决这个问题。

一种方式：

if(response.drive=="Manual") {
    .find('[name=drive]')[0].checked = true         
} else {
    .find('[name=drive]')[1].checked = true
}

另一种方式：

.find("input:radio[name='drive'][value='"+ response.drive +"']")[0].checked = true.end()

这是我的ajax成功函数用于填充表单值的方式。

.success(function(response) {
                    // Populate the form fields with the data returned from server
                    response = jQuery.parseJSON(response)
                    $('#editVehicle')

                            .find('[name="vehicle_id"]').val(response.vehicle_id).end()
                            .find('[name="vehicle_name"]').val(response.vehicle).end()
                            .find('[name="seats"]').val(response.seats).end()
                            .find('[name="luggage"]').val(response.luggage).end()
                            .find('[name="doors"]').val(response.doors).end()
                            .find('[name="emission"]').val(response.emission).end()

                            //.find('[name="drive"]').val(response.drive).prop("checked",true).end()
                            //.find('[name="aircon"]').val(response.aircon).prop("checked",true).end()
                            //.find("input:radio[name='drive'][value='"+ response.drive +"']")[0].checked = true.end()

                            //if(response.drive=="Manual"){
                .find('[name=drive]')[0].prop('checked').end()
                            //}else{
                                //.find('[name=drive]')[1].prop('checked')
                            //} 

                            .find('[name="rental"]').val(response.price).end();

                    // Show the dialog
---- -
---- 
---

这是单选按钮的HTML：

<div class="form-group">
    <label for="">Transmission :</label>
    <div class="col-sm-8">
        <label class="radio-inline">
            <input type="radio" name="drive" id="" value="1"> Manual
        </label>
        <label class="radio-inline">
            <input type="radio" name="drive" id="" value="2"> Auto
        </label>                                                                
    </div>
</div>

我该如何正确地做到这一点？

Answer 1

使用

$('#editVehicle').find(':radio[name=drive][value="1"]').prop('checked', true);

样品：

$(function() {
  response = {
    "vehicle_id": 2,
    "vehicle": "RENAULT TWINGO2798",
    "seats": 43,
    "luggage": 5,
    "doors": 34,
    "emission": 455,
    "drive": "Manual",
    "aircon": "Yes",
    "price": "435.000"
  };
  
  console.log(response.drive);
  
  if (response.drive == 'Manual')
    $('#editVehicle').find(':radio[name=drive][value="1"]').prop('checked', true);
  else
    $('#editVehicle').find(':radio[name=drive][value="2"]').prop('checked', true);

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="editVehicle">
  <div class="form-group">
    <label for="">Transmission :</label>
    <div class="col-sm-8">
      <label class="radio-inline">
        <input type="radio" name="drive" id="" value="1">Manual
      </label>
      <label class="radio-inline">
        <input type="radio" name="drive" id="" value="2">Auto
      </label>
    </div>
  </div>
</div>

编辑：

改变它。

if (response.drive == 'Manual'){
                                .find(':radio[name=drive][value="1"]').prop('checked', true)
                            } else {
                                .find(':radio[name=drive][value="2"]').prop('checked', true)
                            }

到

if (response.drive == 'Manual'){
                                $('#editVehicle').find(':radio[name=drive][value="1"]').prop('checked', true)
                            } else
                                $('#editVehicle').find(':radio[name=drive][value="2"]').prop('checked', true)
                            }

$('.editVehicle').on('click', function() {
            // Get the record's ID via attribute
            var id = $(this).attr('data-id');
            var vehicleId = 'vehicleId=' + id;

            $.ajax({
                    url: './includes/ajaxprocess_edit_vehicles.php',
                    method: 'post',
                    data: vehicleId
            }).success(function(response) {
                    // Populate the form fields with the data returned from server
                    response = jQuery.parseJSON(response)
                    $('#editVehicle')

                            .find('[name="vehicle_id"]').val(response.vehicle_id).end()
                            .find('[name="vehicle_name"]').val(response.vehicle).end()
                            .find('[name="seats"]').val(response.seats).end()
                            .find('[name="luggage"]').val(response.luggage).end()
                            .find('[name="doors"]').val(response.doors).end()
                            .find('[name="emission"]').val(response.emission).end();

                            if (response.drive == 'Manual'){
                                $('#editVehicle').find(':radio[name=drive][value="1"]').prop('checked', true)
                            } else {
                                $('#editVehicle').find(':radio[name=drive][value="2"]').prop('checked', true)
                            }   



    $('#editVehicle').find('[name="rental"]').val(response.price).end();

                        // Show the dialog
                        bootbox
                                .dialog({
                                        title: 'Edit This Vehicle',
                                        message: $('#editVehicle'),
                                        show: false // We will show it manually later
                                })
                                .on('shown.bs.modal', function() {
                                        $('#editVehicle')
                                                .show()                       // Show the edit form
                                                .formValidation('resetForm'); // Reset form
                                })
                                .on('hide.bs.modal', function(e) {
                                        // Bootbox will remove the modal (including the body which contains the edit form)
                                        // after hiding the modal
                                        // Therefor, we need to backup the form
                                        $('#editVehicle').hide().appendTo('body');
                                })
                                .modal('show');
                });
        });

Answer 2

您可以为每个单选按钮提供一个ID，然后：

$("#drive_1").attr('checked', 'checked');

使用AJAX响应设置单选按钮

2 个答案: