Question

如何解析类似的XML文件（此文件只是基本输出）以获取特定的字段值。例如，字段名称＆＃34; len＆＃34;？

中的值和大小

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="pdml2html.xsl"?>
<!-- You can find pdml2html.xsl in /usr/share/wireshark or at http://anonsvn.wireshark.org/trunk/wireshark/pdml2html.xsl. -->
<pdml version="0" creator="wireshark/1.8.5" time="Sun May 10 00:54:17 2015" capture_file="">
<packet>
  <proto name="geninfo" pos="0" showname="General information" size="60">
    <field name="num" pos="0" show="3" showname="Number" value="3" size="60"/>
    <field name="len" pos="0" show="60" showname="Frame Length" value="3c" size="60"/>
  </proto>
</packet>
<packet>
  <proto name="geninfo" pos="0" showname="General information" size="95">
    <field name="num" pos="0" show="5" showname="Number" value="5" size="95"/>
    <field name="len" pos="0" show="95" showname="Frame Length" value="5f" size="95"/>
  </proto>
<packet>

Answer 1

您可以使用序列化来获取所有数据

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";

        static void Main(string[] args)
        {

            PDML pdml = new PDML()
            {
                packet = new List<Packet>(){
                    new Packet(){
                        proto = new Proto(){
                            name = "geninfo",
                            pos = 0,
                            showname = "General information",
                            size= 60,
                            field = new List<Field>(){
                                new Field(){
                                    name = "num",
                                    pos= 0,
                                    show = 3,
                                    showname = "Number", 
                                    value= "3",
                                    size = 60
                                },
                                new Field(){
                                    name= "len",
                                    pos= 0,
                                    show = 60,
                                    showname = "Frame Length",
                                    value = "3c",
                                    size = 60
                                }
                            }
                        }
                    },
                    new Packet(){
                        proto = new Proto(){
                            name = "geninfo",
                            pos = 0,
                            showname = "General information",
                            size = 95,
                            field = new List<Field>(){
                                new Field(){
                                    name= "num",
                                    pos = 0,
                                    show = 5,
                                    showname = "Number",
                                    value = "5",
                                    size = 95
                                },
                                new Field(){
                                    name = "len",
                                    pos = 0,
                                    show = 95,
                                    showname = "Frame Length",
                                    value = "5f",
                                    size = 95
                                }
                            }
                        }
                    }
                }
            };

            XmlSerializer serializer = new XmlSerializer(typeof(PDML));

            StreamWriter writer = new StreamWriter(FILENAME);
            serializer.Serialize(writer, pdml);
            writer.Flush();
            writer.Close();
            writer.Dispose();

            XmlSerializer xs = new XmlSerializer(typeof(PDML));
            XmlTextReader reader = new XmlTextReader(FILENAME);
            PDML newPDML = (PDML)xs.Deserialize(reader);
        }
    }
}

[XmlRoot("pdml")]
public class PDML
{
    [XmlElement("packet")]
    public List<Packet> packet {get;set;}
}
[XmlRoot("packet")]
public class Packet
{
    [XmlElement("proto")]
    public Proto proto { get; set; }
}
[XmlRoot("proto")]
public class Proto
{
    [XmlAttribute("name")]
    public string name { get; set; }
    [XmlAttribute("pos")]
    public int pos { get; set; }
    [XmlAttribute("showname")]
    public string showname { get; set; }
    [XmlAttribute("size")]
    public int size { get; set; }
    [XmlElement("field")]
    public List<Field> field { get; set; }
}

[XmlRoot("field")]
public class Field
{
    [XmlAttribute("name")]
    public string name { get; set; }
    [XmlAttribute("pos")]
    public int pos { get; set; }
    [XmlAttribute("show")]
    public int show { get; set; }
    [XmlAttribute("showname")]
    public string showname { get; set; }
    [XmlAttribute("value")]
    public string value { get; set; }
    [XmlAttribute("size")]
    public int size { get; set; }
}

如何解析pdml xml文件

1 个答案: