我正在尝试使用HashMap构建一个JTree,其中Values为主要类别,Keys为子类别。基本上它看起来像这样:
Movies
-Marvel
-The Avengers
-Guardians of the Galaxy
-James Bond
-Casino Royale
-Skyfall
现在,当我尝试构建树时,我得到一对一的层次结构,其中每个键都被分配了一个新类别,即使已经存在与String匹配的类别。它看起来像这样:
Movies
-Marvel
-The Avengers
-Marvel
-Guardians of the Galaxy
以下是我的代码。如何搜索节点以确保我最终没有任何重复的类别?
public class JTree extends JFrame {
private javax.swing.JTree genreTree;
private JPanel panel1;
public JTree() throws IOException{
super("Genre Search");
setContentPane(panel1);
pack();
setDefaultCloseOperation(WindowConstants.HIDE_ON_CLOSE);
setVisible(true);
setSize(new Dimension(500,500));
genreTree.setModel(null);
HashMap<String, String> hash = new HashMap<String, String>();
hash.put("Avengers","Marvel");
hash.put("Guardians","Marvel");
hash.put("Casino Royale","James Bond");
hash.put("Skyfall","James Bond");
String genreName = "Movies";
DefaultMutableTreeNode genreMainTree = new
DefaultMutableTreeNode(genreName);
DefaultMutableTreeNode mediaTitleNode = new DefaultMutableTreeNode("");
DefaultMutableTreeNode universeTitleNode = new
DefaultMutableTreeNode("");
Set<String> keys = hash.keySet();
Collection<String> values = hash.values();
ArrayList<Map.Entry<String,String>> copy = new
ArrayList<Map.Entry<String, String>>();
copy.addAll(hash.entrySet());
for (Map.Entry<String,String> e : copy){
mediaTitleNode = new DefaultMutableTreeNode(e.getKey());
universeTitleNode = new DefaultMutableTreeNode(e.getValue());
genreMainTree.add(universeTitleNode);
universeTitleNode.add(mediaTitleNode);
}
genreTree.setModel(new DefaultTreeModel(genreMainTree));
}
}
答案 0 :(得分:3)
如何搜索节点以确保我最终没有任何重复的类别?
保持地图键入类别,并使用它的节点进行评估。
Map<String, DefaultMutableTreeNode> categoryToNode = new HashMap<>();
迭代时,检查此Map是否包含类别Node:
例如:
DefaultMutableTreeNode universeTitleNode = categoryToNode.get(e.getValue());
if (universeTitleNode == null ){
universeTitleNode = new DefaultMutableTreeNode(e.getValue());
categoryToNode.put(e.getValue(), universeTitleNode);
genreMainTree.add(universeTitleNode);
}
mediaTitleNode = new DefaultMutableTreeNode(e.getKey());
universeTitleNode.add(mediaTitleNode);