Question

我试图从String list（Array）中只取出一个对应用户输入（数字）的值。如果用户输入数字4，结果应该是60.这是我试图完成的代码。错误是不兼容的int和字符串（当然），但除此之外，我确信我在其他地方也犯了错误。我希望数组在没有对象和类的情况下尽可能简单。

RSA_free()

Answer 1

也许我误解了这个问题，但听起来你想要的只是：

if(inputNumber >= 0 && inputNumber < someArray.length) {
  System.out.printf("The Number %d corresponds to String %s\n", inputNumber, someArray[inputNumber]);
} else {
  // you don't really show how you want to handle this case...
}

目前还不清楚VALID_NUMBERS的目的是什么。

修改

我的意思是你应该完全替换for循环：

import java.util.Scanner;
public class FindStringValue {

  final String[] someArray = {"20", "30", "40", "50", "60", "70", "80", "90"};

  public static void main(String[] args) {

    Scanner in = new Scanner(System.in);
    System.out.print("Enter a number from 0-7 >> ");
    int inputNumber = in.nextInt();

    if(inputNumber >= 0 && inputNumber < someArray.length) {
      System.out.printf("The Number %d corresponds to String %s\n", inputNumber, someArray[inputNumber]);
    } else {
      // you don't really show how you want to handle this case...
    }
  }
}

Answer 2

您不需要检查数组并进行任何比较，因为您要删除元素索引。您可以通过以下代码段实现目标：

public static void main(String[] args) {

    String[] someArray = {"20", "30", "40", "50", "60", "70", "80", "90"};

    int inputNumber;
    boolean foundIt = false;

    Scanner in = new Scanner(System.in);
    System.out.print("Enter a number from 0-7 >> ");
    inputNumber = in.nextInt();
    in.close();
    LinkedList<String> list = new LinkedList(Arrays.asList(someArray));
    list.remove(inputNumber);
    String []newArray = list.toArray(new String[list.size()]);
    System.out.println("The Number " + inputNumber + " corresponds to String  " + someArray[inputNumber]);
}

Answer 3

我完全取消了数组，只需使用此处所示的List。

public static void main(String[] args){

    List<String> numbers = Arrays.asList("20", "30", "40", "50", "60", "70", "80", "90");

    int inputNumber;

    Scanner in = new Scanner(System.in);
    System.out.print("Enter a number from 0-7 >> ");
    inputNumber = in.nextInt();
    in.close();

    if(inputNumber < numbers.size()) //validity check of input value
    {
        System.out.println("The Number "+ inputNumber + " corresponds to String  "+ numbers.get(inputNumber));
    }

 }

打印与Array中的数字匹配的String

3 个答案:

修改