Question

我试图将一些数据插入到android数据库中但是它的抛出约束错误。我无法捕获此异常的原因。这是我的数据库创建java文件。

package Database;

import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

public class VendorTable extends SQLiteOpenHelper {

    // All Static variables
    // Database Version
    private static final int DATABASE_VERSION = 1;

    // Database Name
    private static final String DATABASE_NAME = "ghartrends";

    // Contacts table name
    private static final String TABLE_NAME = "fixingvendor";

    // Contacts Table Columns names
    private static final String FIRM_NAME = "firm_name";
    private static final String OWNER_NAME = "owner_name";
    private static final String CONTACT = "contact";
    private static final String EMAIL_ID = "email_id";
    private static final String ADDRESS = "address";
    private static final String WORKSCOPE = "workscope";
    private static final String VENDOR_ID = "vendor_id";
    private static final String ACTIVATION = "activation_code";

    public VendorTable(Context context) {
        super(context, DATABASE_NAME, null, DATABASE_VERSION);
    }

    // Creating Tables
    @Override
    public void onCreate(SQLiteDatabase db) {
        String CREATE_FIXINGVENDOR_TABLE = "CREATE TABLE " + TABLE_NAME + "("
            + FIRM_NAME + " TEXT," + OWNER_NAME + " TEXT,"
            + CONTACT + " TEXT,"+ EMAIL_ID +" TEXT,"+ ADDRESS +" TEXT,"
            +WORKSCOPE +" TEXT,"+ VENDOR_ID +" TEXT,"+ ACTIVATION +" TEXT               PRIMARY KEY"+ ")";
        db.execSQL(CREATE_FIXINGVENDOR_TABLE);
    }

    // Upgrading database
    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // Drop older table if existed
        db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);

        // Create tables again
        onCreate(db);
    }

    public String GetActivationCode(){
        String activationcode;
        String selectQuery = "SELECT activation_code FROM " + TABLE_NAME;
        SQLiteDatabase db = this.getWritableDatabase();

        Cursor cursor = db.rawQuery(selectQuery, null);
        do{
            activationcode=cursor.getString(8);
        } while(cursor.moveToNext());

        return activationcode;
    }

    public void addVendorInfo(String firmname,String ownername,String contact,String emailid,
                              String address,String workscope,String vendorid, String activationcode) {
        SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(FIRM_NAME, firmname); 
        values.put(OWNER_NAME, ownername);
        values.put(CONTACT, contact);
        values.put(EMAIL_ID, emailid);
        values.put(ADDRESS, address);
        values.put(WORKSCOPE, workscope);
        values.put(VENDOR_ID, vendorid);
        values.put(ACTIVATION, activationcode);

        // Inserting Row
        db.insert(TABLE_NAME, null, values);
        db.close(); // Closing database connection
    }
}

这是它正在抛出的错误

05-10 00:00:46.478: E/Database(527): Error inserting owner_name=kkhgfd    address=hgds workscope=jhfd vendor_id=TSSRANCY47MB08IEIDSB email_id=o@f.n  contact=9877654345 firm_name=hjgfds activation_code=0NA
05-10 00:00:46.478: E/Database(527): android.database.sqlite.SQLiteConstraintException: error code 19: constraint failed
05-10 00:00:46.478: E/Database(527):    at android.database.sqlite.SQLiteStatement.native_execute(Native Method)
05-10 00:00:46.478: E/Database(527):    at android.database.sqlite.SQLiteStatement.execute(SQLiteStatement.java:61)
05-10 00:00:46.478: E/Database(527):    at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1582)
05-10 00:00:46.478: E/Database(527):    at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1426)
05-10 00:00:46.478: E/Database(527):    at Database.VendorTable.addVendorInfo(VendorTable.java:81)
05-10 00:00:46.478: E/Database(527):    at com.ghartrends.SignUp$1.onClick(SignUp.java:88)
05-10 00:00:46.478: E/Database(527):    at android.view.View.performClick(View.java:2485)
05-10 00:00:46.478: E/Database(527):    at android.view.View$PerformClick.run(View.java:9080)
05-10 00:00:46.478: E/Database(527):    at android.os.Handler.handleCallback(Handler.java:587)
05-10 00:00:46.478: E/Database(527):    at android.os.Handler.dispatchMessage(Handler.java:92)
05-10 00:00:46.478: E/Database(527):    at android.os.Looper.loop(Looper.java:123)
05-10 00:00:46.478: E/Database(527):    at android.app.ActivityThread.main(ActivityThread.java:3683)
05-10 00:00:46.478: E/Database(527):    at java.lang.reflect.Method.invokeNative(Native Method)
05-10 00:00:46.478: E/Database(527):    at java.lang.reflect.Method.invoke(Method.java:507)
05-10 00:00:46.478: E/Database(527):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839)
05-10 00:00:46.478: E/Database(527):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597)
05-10 00:00:46.478: E/Database(527):    at dalvik.system.NativeStart.main(Native Method)

从错误的上面两行可以看出，我试图在数据库中存储的参数都没有。

那么我无法配置的问题在哪里。

Answer 1

您只将activation_code字段定义为主键，这意味着activation_code中不能有两个或多个具有相同值的记录。发生异常是因为您尝试第二次插入带有activation_code=0NA的记录。

如果activation_code不是密钥，那么我认为更好的方法是根据其他字段值生成此字段值。

错误在android sqlite约束失败中插入数据

1 个答案: