Question

我有一个django应用程序，您想要显示跟踪到特定图库的所有图像，但我收到错误：＆＃39; GalleryDetailsView1＆＃39;对象没有属性＆＃39; gallery＆＃39;

模型

class Gallery(models.Model):
    title = models.CharField(max_length=200)
    description = models.TextField()
    image = ThumbnailerImageField(upload_to='paint/%Y/%m/%d')

    class Meta:
        verbose_name = "Gallery"
        verbose_name_plural = " Galleries"

    def __unicode__(self):
        return self.title


class Paint(models.Model):
    AVAILABLE = "Available"
    NOT_AVAILABLE = "Not available"
    STATUS_PAINT = (
        (AVAILABLE, u"Dostępny"),
        (NOT_AVAILABLE, u"Nie dostępny")
    )
    title = models.CharField(max_length=200)
    gallery = models.ForeignKey(Gallery, related_name='paint_set')
    paint = ThumbnailerImageField(upload_to='paint/%Y/%m/%d')
    price = models.CharField(max_length=50, blank=True, null=True)
    status = models.CharField(choices=STATUS_PAINT, default=AVAILABLE, max_length=50)

视图

class GalleryList(generic.ListView):
    model = Gallery
    context_object_name = "list"
    template_name = "www/gallery_list.html"


class GalleryDetailsView1(generic.DetailView):
    context_object_name = "images1"
    template_name = "www/gallery_details1.html"

    def get_queryset(self):
        return Gallery.objects.get(pk=self.kwargs['pk']).paint_set.all()

模板：gallery_details1

{% extends "base.html" %}
{% load thumbnail %}

{% block content %}


{% for i in images1 %}

{{ i.title }}
<hr>
{% endfor %}


{% endblock %}

{% block content_bottom %}{% endblock content_bottom %}

Answer 1

当您提出要求时，您必须以某种方式通过图库pk。例如，作为网址的一部分，然后在视图中从self.kwargs['gallery_pk']（gallery_pk位取决于您的实施）获取它：

url(r'^api/gallery/(?P<gallery_pk>\d+)/paintset$', GalleryDetailsView1.as_view())

然后您可以返回

self.get_object().paint_set.all()

作为您的查询集。

最后但并非最不重要的是，图库字段定义中的related_name参数应为"paint_set"才能生效。

视图详细信息中的外键

1 个答案: