Question

我在这里尝试做的是读取一个文件并计算每个字符。每个字符都应该为“int count”添加+1，然后打印出“int count”的值。

我希望我想要做的事情很明确。

{{1}}

Answer 1

添加catch块以检查异常
从hasNext（“”）

转到下一个标记

    cCount = new Scanner(new BufferedReader(new  FileReader("greeting")));
    while (cCount.hasNext()) {
            count = count + (cCount.next()).length();
    }

Answer 2

使用java 8 Stream API，您可以按照以下方式执行

package example;

import java.io.IOException;
import java.nio.charset.StandardCharsets;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.stream.Collectors;
import java.util.stream.Stream;

public class CountCharacter {

    private static int count=0;

    public static void main(String[] args) throws IOException {
        Path path = Paths.get("greeting");
        try (Stream<String> lines = Files.lines(path, StandardCharsets.UTF_8)) {
            count = lines.collect(Collectors.summingInt(String::length));
        }
        System.out.println("The number of charachters is "+count);
    }

}

Answer 3

好吧，如果您正在寻找一种方法，只计算所有字符和整数，而没有任何空格和类似＆＃39; tab＆＃39;，＆＃39;输入＆＃39;等等。然后你可以先用这个函数删除那些空格：

st.replaceAll("\\s+","")

然后你会做一个字符串计数

String str = "a string";
int length = str.length( );

Answer 4

首先，为什么不使用try { }

使用catch(Exception e)

BufferedReader reader = null;
try {
reader = new BufferedReader(new    FileReader("greetings.txt"));
String line = null;
String text = "";
while ((line = reader.readLine()) != null) {
     text += line;
}
int c = 0; //count of any character except whitespaces
 // or you can use what @Alex wrote
 // c = text.replaceAll("\\s+", "").length();    
for (int i = 0; i < text.length(); i++) {
    if (!Character.isWhitespace(text.charAt(i))) {
        c++;
    }
}
System.out.println("Number of characters: " +c);
} catch (IOException e) {
     System.out.println("File Not Found");
} finally {
     if (reader != null) { reader.close();
     }
}

我正在尝试从内部文件中计算字符数

4 个答案: