Question

我需要计算.c文件中条件（三元）和逗号运算符的出现次数。问题是条件运算符可以是任何类型（它可以是最简单的运算符，它可以是非常长的复合运算符）。这同样适用于逗号运算符。

我绝对不知道该怎么做。我认为使用正则表达式匹配来找到它，但它可能不是最好的选择。你有更好的想法吗？

编辑这里是一些用于分析的输入文件：

<link rel="import" href="../bower_components/polymer/polymer.html">
<link rel="import" href="../bower_components/core-input/core-input.html">

<polymer-element name="count-button" extends="button" on-click="increment">
  <template>
    <content>Increment: </content>
  </template>

  <script>
    Polymer({
      counter: 0,
      increment: function(e, detail, sender) {
          this.counter++;
          alert(this.counter);
      }
    })
  </script>
</polymer-element>

输出为：18个三元运算符

Answer 1

按照您当前的说明，我会编写如下代码：

def match(operator, filename):
    with open(filename, "r") as f:
        data = f.read()
        n = 0
        op_len = len(operator)
        match = data.find(operator)
        while match != -1:
            n += 1
            data = data[match + op_len:] # cut checked part
            match = data.find(operator)

        if n > 0:
            print """Found {0} "{1}" in {2}""".format(n, operator, filename)
        else:
            print """No "{0}" in {1}""".format(operator, filename) 


if __name__ == "__main__":
    operators = ["==", ">", "<", ","]  # + any other you want 
    for op in operator:
        match(op, "main.c")

计算条件和逗号运算符

1 个答案: