Question

当我尝试为我的addressline_1分配一个值时，我无法设置addressline_1的undefined属性，这是一个父对象物理的子对象。感谢是否有人可以告诉我如何解决这个问题？提前谢谢。

$scope.editCompany = function(){
  $scope.submitCompany =[{phone:[]}]; 
  $scope.submitCompany[0].name = "Some Company";
  $scope.submitCompany[0].email = "company@example.com";
  $scope.submitCompany[0].is_active = "TRUE";
  $scope.submitCompany[0].physical.addressline_1 = "77 Example rd";
}

我也试过以下但没有运气。

$scope.editCompany = function(){
  $scope.submitCompany =[{phone:[]},{physical:{addressline_1:"",addressline_2:"",addressline_3:"",addressline_4:"",city:"", region:"",country:"", post_code:""}}]; 
  $scope.submitCompany[0].name = "Some Company";
  $scope.submitCompany[0].email = "company@example.com";
  $scope.submitCompany[0].is_active = "TRUE";
  $scope.submitCompany[0].physical.addressline_1 = "77 Example rd";
}

Answer 1

在尝试设置其属性之前，您需要先创建physical对象：

$scope.editCompany = function(){
  $scope.submitCompany =[{phone:[]}]; 
  $scope.submitCompany[0].name = "Some Company";
  $scope.submitCompany[0].email = "company@example.com";
  $scope.submitCompany[0].is_active = "TRUE";
  $scope.submitCompany[0].physical = {};
  $scope.submitCompany[0].physical.addressline_1 = "77 Example rd";
};

或更清晰的语法：

$scope.editCompany = function () {
    $scope.submitCompany = [{
        phone: [],
        name: "Some Company",
        email: "company@example.com",
        is_active: "TRUE",
        physical: {
            addressline_1: "77 Example rd"
        }
    }];
};

Answer 2

您在设置属性之前将对象分配给physical属性是正确的，但是您将其放在$scope.submitCompany[1].physical而不是$scope.submitCompany[0].physical。

将physical属性放在与phone属性相同的对象中：

$scope.editCompany = function(){
  $scope.submitCompany = [ { phone: [], physical: {} } ]; 
  $scope.submitCompany[0].name = "Some Company";
  $scope.submitCompany[0].email = "company@example.com";
  $scope.submitCompany[0].is_active = "TRUE";
  $scope.submitCompany[0].physical.addressline_1 = "77 Example rd";
}

Answer 3

做一些小改变......

$scope.editCompany = function(){
  $scope.submitCompany =[{phone:[]},{physical:{addressline_1:"",addressline_2:"",addressline_3:"",addressline_4:"",city:"", region:"",country:"", post_code:""}}]; 
 ....
  $scope.submitCompany[1].physical.addressline_1 = "77 Example rd"; // instead $scope.submitCompany[0].physical.addressline_1
}

无法设置未定义子对象的属性

3 个答案: