我是JavaScript的新手,我正在通过在线教程学习它。当前表达式是关于函数表达式的使用,特别是 - 从函数内部返回函数表达式。
以下是代码:
//array of all available rides, with respective wait times
var parkRides = [["Birch Bumpers", 40], ["Pines Plunge", 55], ["Cedar Coaster", 20], ["Ferris Wheel of Firs", 90]];
//array of fast pass rides, indicating next up ride
var fastPassQueue = ["Cedar Coaster", "Pines Plunge", "Birch Bumpers", "Pines Plunge"];
//function to build fast pass queue using array
function buildTicket(allRides, passRides, pick) {
//if user has picked the first ride in fast pass queue, alert so...
if(pick == passRides[0]) {
//remove first item from queue using shift and store it in a var
var pass = passRides.shift();
//return function expression here
return function () {
alert("QuicK!! You've got a fast pass to " + pass + "!");
}; //return ends with a ;
}
else {
for (var i = 0; i < allRides.length; i++) {
if(pick == allRides[i][0]) {
//return a function expression here
return function () {
alert("A ticket is printing for " + allRides[i][0] +"!\n"+ " Your wait time is about " + allRides[i][1] + " minutes.");
};
}
}
}
}
//use function buildticket
var wantsRide = "Pines Plunge";
var ticket = buildTicket(parkRides, fastPassQueue, wantsRide);
//execute function expression by calling ticket()
ticket();
我正在使用MS Visual Studio代码,在代码的最后,我收到一个错误和一个警告,即使代码成功运行,我得到了所需的结果,具体取决于wantsRide
变量。但是,我无法理解错误和警告的原因。
在屏幕底部(下面的屏幕截图),我得到1个十字和1个感叹号图标,我认为这意味着1个错误和1个警告。
但是当我点击它时,我会在条形图顶部显示一个突出显示的区域! Function inside loop
,并突出显示这些行:
return function () {
alert("A ticket is printing for " + allRides[i][0] +"!\n"+ " Your wait time is about " + allRides[i][3] + " minutes.");
};
这里似乎有什么问题?我知道它是for
循环中的函数表达式,但为什么会生成警告?是因为if(pick==allRides[i][0])
语句可能永远不会成立,所以函数表达式永远不会被执行吗?
答案 0 :(得分:0)
在黑暗中这是一个镜头,但可能是MSVS无法理解你的函数返回的是什么(即另一个函数)。
这个问题可能会对这个问题有所启发:
Create javascript function that works with intellisense
(或者我可能完全是在错误的树上狂奔)
因此,如果将返回值定义为“function”类型的变量并在以后适当时重新定义它,它在MSVS中可能会更好。 类似的东西:
//function to build fast pass queue using array
function buildTicket(allRides, passRides, pick) {
var func = new function() {}
//if user has picked the first ride in fast pass queue, alert so...
if(pick == passRides[0]) {
//remove first item from queue using shift and store it in a var
var pass = passRides.shift();
func = function () {
alert("QuicK!! You've got a fast pass to " + pass + "!");
}; //return ends with a ;
//return function expression here
return func;
}
else {
for (var i = 0; i < allRides.length; i++) {
if(pick == allRides[i][0]) {
func = function () {
alert("A ticket is printing for " + allRides[i][0] +"!\n"+ " Your wait time is about " + allRides[i][1] + " minutes.");
};
//return a function expression here
return func;
}
}
}
}
虽然这并不能解释为什么MSVS会抱怨第二次回复而不是第一次回复(或两者),所以我可能完全错了(我没有或使用过MSVS)。