Question

我正在尝试从GeoJSON功能循环遍历特定属性，但遇到了一些麻烦。以下是我尝试在本地服务器上实现它的方法：

$.getJSON('myData.geojson', function(data) {
    for (var i = 0; i < data.length; i++) {
        var obj = data[i];
        console.log(obj.properties[0].ID);
    }
});

这是一小部分数据样本：

"type": "FeatureCollection",
"crs": { "type": "name", "properties": { "name": "urn:ogc:def:crs:OGC:1.3:CRS84" } },
"features": [
{ "type": "Feature", "properties": { "ID": 1, "Name": "ABC Cleaner" }, "geometry": { "type": "Point", "coordinates": [ [ [ [ 46.879682, -110.362566 ] } },
{ "type": "Feature", "properties": { "ID": 2, "Name": "Rapid X Cleaner" }, "geometry": { "type": "Point", "coordinates": [ 46.882224, -110.350167] } },
{ "type": "Feature", "properties": { "ID": 3, "Name": "Ace Cleaner" }, "geometry": { "type": "Point", "coordinates": [ 46.885817, -110.338966 ] } } ...

例如，如果我要打印所有ID或Name属性，我该怎么做？

Answer 1

您需要在循环中使用以下代码

$(document).ready(function () {
$.getJSON('http://f.cl.ly/items/2k3d2Y3X1m0c3f0l3W3f/sample.json',
 function (data) {
    var result = data.objects.myData.geometries;
        for (var i = 0; i < result.length; i++) {
           alert(result[i].properties.ID)
         }
   });
  })

循环通过GeoJSON属性

1 个答案: