Question

您好我正在加入表格以返回数据，但我希望按特定位置对数据进行分组，并计算/求和与该位置相关的值目前我只能检索数据，但它不会对该位置的值求和/计数这是我的查询

    select brand_locations.locationName,campaign_stats.clicks,
    campaign_stats.impressions,
    campaign_stats.day,brand_locations.city,

    click_actions.walkTo,click_actions.showMap,
    click_actions.call,click_actions.coupon,driveTo,campaigns_details.state 
    from campaign_stats
             inner join campaigns_details on campaign_stats.campaignId = campaigns_details.campaignId               
             inner join click_actions on click_actions.campaignId=campaign_stats.campaignId
             inner join brand_locations on brand_locations.brandId = campaigns_details.brandId
             where brand_locations.city = 'cape town'

输出

bellville       58
water front     12
bellville        4
bellville        1
century city     2
century city     4

我的目标是

bellville       63
water front     12
century city     6

谢谢

Answer 1

MySQL SUM（）函数检索已经过GROUP BY子句分组操作的表达式的和值。你试过这个选项吗？

select brand_locations.locationName,SUM(campaign_stats.clicks),
campaign_stats.impressions,
campaign_stats.day,brand_locations.city,

click_actions.walkTo,click_actions.showMap,
click_actions.call,click_actions.coupon,driveTo,campaigns_details.state 
from campaign_stats
         inner join campaigns_details on campaign_stats.campaignId = campaigns_details.campaignId               
         inner join click_actions on click_actions.campaignId=campaign_stats.campaignId
         inner join brand_locations on brand_locations.brandId = campaigns_details.brandId
         where brand_locations.city = 'cape town' group by brand_locations.locationName

Answer 2

尝试此查询。我已按位置名称向查询添加了一个组，并使用函数sum来计算总点击次数。

select brand_locations.locationName,SUM(campaign_stats.clicks) as campaign_stats_cnt,
    sum(campaign_stats.impressions) as impressions_cnt,
    campaign_stats.day,brand_locations.city,

    click_actions.walkTo,click_actions.showMap,
    click_actions.call,click_actions.coupon,driveTo,campaigns_details.state 
    from campaign_stats
             inner join campaigns_details on campaign_stats.campaignId = campaigns_details.campaignId               
             inner join click_actions on click_actions.campaignId=campaign_stats.campaignId
             inner join brand_locations on brand_locations.brandId = campaigns_details.brandId
             where brand_locations.city = 'cape town' group by brand_locations.locationName

Answer 3

您可以使用sum()从您获得的结果中获得所需的结果

SELECT title, SUM(count) 
FROM (resultQuery) 
GROUP BY title

注意：将标题替换为第一列的name，将count替换为第二列的名称，将resultQuery替换为他们查询您的名称

是的，这是执行它的hacky子查询方式....

在Sql中选择distinct，count和groupBy

3 个答案: