Question

所以，我对java很新，我想在命令行中尝试调试，即在有一些错误的代码上使用jdb。我正在修改这段代码：

import java.util.Scanner;
import java.io.File;

class LetterHome{

   static final int MAX_CODE = 5;

   public static void main(String[] args) throws Exception{
      Scanner in = new Scanner(new File(args[0]));
      String phrase;
      int sentenceCode, modifierCode;

      System.out.println("Dear Mom and Dad:\n");


      while( in.hasNext() ){

         sentenceCode = in.nextInt();
         modifierCode = in.nextInt();


         if( (sentenceCode < 1) || (sentenceCode >= MAX_CODE) ) {
            System.out.println(sentenceCode + " is not a valid sentence code");
            continue;
         }


         if( sentenceCode == 1 ){
            if( modifierCode == 1 ){
               phrase = "great";
            }else if( modifierCode == 2 ){
               phrase = "ok";
            }else{
               phrase = "ERROR";
            }
            System.out.println("My classes are going " + phrase + ".");

         }else if( sentenceCode == 2 ){
            phrase = weatherModifier(modifierCode);
            System.out.println("The weather here has been " + phrase + ".");

         }else if( sentenceCode == 3 ){
            if( modifierCode == 1 ){
               phrase = "after the quarter ends";
            }else if( modifierCode == 2 ){
               phrase = "in a few weeks";
            }else if( modifierCode == 3 ){
               phrase = "next weekend";
            }else{
               phrase = "ERROR";
            }
            System.out.println("I plan to come home for a visit " + phrase + ".");

         }else if( sentenceCode == 4 ){
            System.out.println("Do you think you could send me $" + modifierCode + "?");
            System.out.println("I have to buy another book for one of my classes.");

         }else if( sentenceCode == 5 ){
            if( modifierCode == 1 ){
               phrase = "cookies";
            }else if( modifierCode == 2 ){
               phrase = "stuff";
            }else; if( modifierCode == 3 ){
               phrase = "money";
            }else{
               phrase = "ERROR";
            }
            System.out.println("Thanks for the " + phrase + " you sent.");
         }
      }
   }


   static String weatherModifier(int m) {
      String word=null;


      if(m == 1)
         word = "great";
      if(m == 2)
         word = "foggy";
      if(m == 3)
         word = "hot";
      if(m == 4)
         word = "cold";
      if(m == 5)
         word = "variable";
      if( m<1 && m>5)
         word = "ERROR";

      return word;
   }

}

我已经找到了＆＃34 ;;＆＃34;那是不合适的。我知道有些东西与最终分配给术语的值有关（我认为），因为当我编译程序时，我得到了这个输出：

Dear Mom and Dad:
//
//             5 is not a valid sentence code
//             My classes are going great.
//             The weather here has been foggy.
//             I plan to come home for a visit in a few weeks.

而不是上课和＃34;伟大＆＃34;，我得到＆＃34;模糊＆＃34;，我在运行jdb时注意到了。我用这个数据文件运行代码：

代码本身会打印一个模板，其中包含数据文件中列出的可能选项，您可能已经注意到了这些选项。以下是完整的可能性列表：

//             1. My classes are going _____.
//                  1. great
//                  2. ok
//             2. The weather here has been _____.
//                  1. great
//                  2. foggy
//                  3. hot
//                  4. cold
//                  5. variable
//             3. I plan to come home for a visit _____.
//                  1. after the quarter ends
//                  2. in a few weeks
//                  3. next weekend
//             4. Do you think you could send me $_____?
//                I have to buy another book for one of my classes.
//             5. Thanks for the _____ you sent.
//                  1. cookies
//                  2. stuff
//                  3. money

但是，我不确定代码中的逻辑是什么。有小费吗？如果我需要澄清，请告诉我。感谢。

Answer 1

您在;功能的if (m==2);末尾添加了额外的weatherModifier。删除它！

Answer 2

我想出了问题，实际上：

它在＆＃34; if（（sentenceCode＆lt; 1）||（sentenceCode＆gt; = MAX_CODE））＆＃34;

我不得不改变＆＃34;＆gt; =＆＃34;到＆＃34;＆gt;＆＃34;

确定导致印刷错误的逻辑错误

2 个答案: