Question

我有一组数据。在a中有10个字段，b中有10个字段

var a = [ "siddharth", "sid", "anything", "something", "nothing", ]
var b = [ "23", "67", "10", "10", "90" ]

我正在尝试从这些数组创建JSON作为密钥a b 作为值，如下所示：

{  "siddharth" : "23",  "sid" : "67" }

如何使用javascript或jquery实现此目的。我目前的代码是

 var convert = '{'+datatest.columnHeaders[i].name +":"+datatest.rows[0][i]+'}';
         pair   = convert;/*JSON.stringify(convert);*/
         array.pairArray.push(pair);

Answer 1

假设两个数组的长度始终相同：

var obj = {}
for (var i = 0; i < a.length; i++) {
    //or check with: if (b.length > i) { assignment }
    obj[a[i]] = b[i]
}

Answer 2

＆＃13;

var a = [ "siddharth", "sid", "anything", "something", "nothing" ];
var b = [ "23", "67", "10", "10", "90" ];

var c = {};
$.each( a, function(i,v) {
  c[ v ] = b[ i ];
});

$('body').append( JSON.stringify(c) );
//Output: {"siddharth":"23","sid":"67","anything":"10","something":"10","nothing":"90"}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

＆＃13;

Answer 3

此示例等于tymeJVs示例，但对数组使用forEach循环。对我来说，它看起来更短。

var obj = {};
a.forEach(function(item, i) {
    obj[item] = b[i];
});
console.log(JSON.stringify(obj)); // {"siddharth":"23","sid":"67","anything":"10","something":"10","nothing":"90"}

Answer 4

您可以创建普通对象并将其用作映射容器：

var a = [ "siddharth", "sid", "anything", "something", "nothing" ];
var b = [ "23", "67", "10", "10", "90" ];
var obj = {};
for ( i = 0; i < a.length; i++) {
    obj[a[i]] = b[i];
}
alert(JSON.stringify(obj));

有关详细信息，请参阅How to create a hash or dictionary object in JavaScript

Answer 5

您需要在名称和值周围加上引号，否则最终会得到{siddharth:23,sid:67}之类的字符串：

// mock the data
var datatest = {
  columnHeaders: [ { name: "siddharth" }, { name: "sid" }, { name: "anything" }, { name: "something" }, { name: "nothing" } ],
  rows: [[ "23", "67", "10", "10", "90" ]]
};

var json = '{';
for (var i = 0; i < datatest.columnHeaders.length; i++) {
  if (i > 0) json += ',';
  json += '"' + datatest.columnHeaders[i].name + '":"' + datatest.rows[0][i]  +'"';
}
json += '}';

// show result in StackOverflow snippet
document.write(json);

Answer 6

最短的我可以使用ES6胖箭头功能，map，reduce＆amp; computed property names

＆＃13;

var a = ["siddharth", "sid", "anything", "something", "nothing", ]
var b = ["23", "67", "10", "10", "90"]

const mergeArrToJSON = (a, b) => a
    .map((item, i) => ({[item]: b[i]})) 
    .reduce((json,val)=>Object.assign({},json,val))

console.log(mergeArrToJSON(a, b))

＆＃13;

Answer 7

如果您愿意添加另一个着名的第三方JavaScript实用程序库

Lodash，使用zipObject：

_.zipObject(a, b);

下划线，使用object：

_.object(a, b);

Answer 8

如果您可以自由使用其他插件，那么

UNDERSCORE

是您正在寻找的

_.object(['moe', 'larry', 'curly'], [30, 40, 50]);
=> {moe: 30, larry: 40, curly: 50}

单行代码。只需包含此js

https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore.js

将两个数组合并为一个javascript对象

8 个答案: