Question

我在点击小部件中的按钮后试图启动服务，但不知何故该服务没有启动。我在互联网上看，并没有找到答案。

这是onUpdate方法

 public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) {

        // Create an intent to launch the service
        Intent serviceIntent = new Intent(context, MyService.class);

        // PendingIntent is required for the onClickPendingIntent that actually
        // starts the service from a button click
        PendingIntent pendingServiceIntent =
                PendingIntent.getService(context, 0, serviceIntent, PendingIntent.FLAG_UPDATE_CURRENT);

        // Get the layout for the App Widget and attach a click listener to the
        // button
        RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.meat);
        appWidgetManager.updateAppWidget(appWidgetIds, views);
        Log.i(TAG, "onUpdate is on");
        views.setOnClickPendingIntent(R.id.button, pendingServiceIntent);
        context.startService(serviceIntent);
        super.onUpdate(context, appWidgetManager, appWidgetIds);

    }

我也试过onRecive方法

@Override
public void onReceive(Context context, Intent intent) {
    Intent intent1 = new Intent (context, MyService.class);
    intent1.setFlags (Intent.FLAG_ACTIVITY_NEW_TASK);
    context.startService (intent1);
    super.onReceive(context, intent);
}

我尝试用吐司信息测试它

public class MyService extends Service {

    Context context = getApplicationContext();

    @Override
    public void onCreate() {
        Toast.makeText(context, "the service started", Toast.LENGTH_SHORT).show();
    }

这是onStartCommand

@Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        timer = new MyCounter(21600000,1000);
        RemoteViews v = new RemoteViews(getPackageName(),R.layout.meat);
        v.setTextViewText(R.id.textView2, getCurrentTime());
        appWidgetManager.updateAppWidget(thisWidget, v);
        timer.start();
        Toast.makeText(context, "the service started", Toast.LENGTH_SHORT).show();
        appWidgetManager.updateAppWidget(thisWidget, v);
        return START_STICKY;
    }

我的清单

    <application
        android:allowBackup="true"
        android:icon="@mipmap/ic_launcher"
        android:label="@string/app_name"
        android:theme="@style/AppTheme" >

       <receiver android:name=".meat" >
            <intent-filter>
                <action android:name="android.appwidget.action.APPWIDGET_UPDATE" />
            </intent-filter>

            <meta-data
                android:name="android.appwidget.provider"
                android:resource="@xml/meat_info" />
        </receiver>

        <service
            android:name=".MyService"
            android:enabled="true"
            android:exported="true" >
            <intent-filter>
                <action android:name="ACTION_WIDGET_CLICK_RECEIVER"/>
            </intent-filter>
        </service>
    </application>

Answer 1

要启动服务，您必须在onReceive中调用startService方法。所以只需替换这一行：

context.startActivity (intent1);

有了这个：

context.startService(intent1);

并且还要确保覆盖启动服务的onStartCommand方法

在窗口小部件中单击按钮后，服务不会启动

1 个答案: