Question

我有一个json字符串和另一个。我必须一起追加，发送到服务器并获取用户ID。我被困在中间。附加字符串未转换为NSURL。

这是我的代码。

- (void)convertingstringtojsondata
{
    NSArray *components = [[NSArray alloc]initWithObjects:ismunicipality,mobilenumberstring,placestring,namestring,  nil];
    NSArray *keys = [[NSArray alloc]initWithObjects:@"is_municipality",@"ph_nbr",@"place",@"reg_name", nil];
    NSLog(@"%@",components);

    NSDictionary *dict = [[NSDictionary alloc]initWithObjects:components forKeys:keys];

    NSLog(@"dict %@", dict);

    NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dict
                                                       options:0
                                                         error:nil];
    NSLog(@"JSON DATA %@", jsonData);

    jsonData= jsonData;

  JSONString = [[NSString alloc] initWithBytes:[jsonData bytes] length:[jsonData length] encoding:NSUTF8StringEncoding];

    NSLog(@"JSON STRING%@",JSONString);
}
-(void)sendjsonforregistration
{
 [self convertingstringtojsondata];

    registerwithserverstring = [[NSMutableString alloc]initWithString:@"http://forthepeople.mcms.net.in/forthepeople_service/registration?reg="];
    [registerwithserverstring appendString:JSONString];

    NSLog(@" appended string %@", registerwithserverstring);

    NSURL *registerURL = [NSURL URLWithString:registerwithserverstring];

    NSLog(@"register URL%@", registerURL);

NSMutableURLRequest * request = [[NSMutableURLRequest alloc]initWithURL:registerURL cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:0];
NSOperationQueue * queue = [[NSOperationQueue alloc]init];
[NSURLConnection sendAsynchronousRequest:request queue:queue completionHandler:^(NSURLResponse * response, NSData * data, NSError * error) {
    NSData * jsonData1 = [NSData dataWithContentsOfURL:registerURL];

    NSLog(@"%@", jsonData1);

    dataDictionary1 = [NSJSONSerialization JSONObjectWithData:jsonData1 options:0 error:&error];

   NSLog(@"DATA DICTIONARY %@", dataDictionary1);

}];
}

问题： - registerURL显示空值...

Answer 1

我建议使用NSURLComponents构建您的网址，它会在您提供的NSURLQueryItem中正确处理查询参数编码。

Answer 2

我认为您需要在转换为NSURl之前对NSString进行编码。你可以做到这一点。

 NSMutableString* registerwithserverstring = [[NSMutableString alloc]initWithString:@"http://forthepeople.mcms.net.in/forthepeople_service/registration/reg=?{\"reg_name‌\":\"ugh\",\"place\":\"Malappuram\",\"ph_nbr\":\"7204412649\",\"is_municipality\":\"1\"}"];

NSString * properlyEncodedString = [registerwithserverstring stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];

NSURL *registerURL = [NSURL URLWithString:properlyEncodedString];

NSLog(@"register URL%@", registerURL);

输出：

Printing description of registerURL:
http://forthepeople.mcms.net.in/forthepeople_service/registration/reg=?%7B%22reg_name%E2%80%8C%E2%80%8B%22:%22ugh%22,%22place%22:%22Malappuram%22,%22ph_nbr%22:%227204412649%22,%22is_municipality%22:%221%22%7D

iOS中的JSON转换问题

2 个答案: