Question

我想逃避＆符号。因为，它假设另一个参数..我想将以下所有这些消息传递给java web服务参数..那个符号符号剪切了消息..请任何人帮忙

我的PHP代码：

$message ="Hi $names \r\n";

$message.="Welcome to Home 2 Office Rider Network. To activate your account \r\n";

$message.="please verify your email using below URL \r\n\n";

$message.="http://localhost/h2orn/php/verify.php?email=$emails&hash=$hash \n\n\n ";
    $message.="Thanks for your interest and support to H2ORN. Kindly reach out to \r\n";
    $message.="'care@h2orn.in' for any queries relating to H2ORN operations.\r\n\n\n";
    $message.="Thanks\r\n";
    $message.="Support Team\r\n\n\n";

$message.="This is automated email message. Please do not reply to this email.\r\n \n\n";

$url = "http://localhost:8084/mail/webresources/EmailTest";
$mail = "toAddress=" . $emails . "&emailbody=" . $message ;
$ch  = curl_init($url);

感谢您提前，

Answer 1

你只是想要对＆符号进行编码，你想对所有的值进行正确的URI编码。您可以使用urlencode function。

执行此操作

$mail = "toAddress=" . urlencode($emails) . "&emailbody=" . urlencode($message) ;
//                     ^^^^^^^^^                            ^^^^^^^^^

如何逃脱＆符号

1 个答案: