Question

在此代码中，单击like按钮后，数据已添加到数据库中。我现在要做的是在添加数据后，我想查询所选项目的总数，并在不加载页面的情况下显示它。

这是我现在的代码：

我的观点：

<p id='state'><i class='fa fa-thumbs-up'></i><span id="likeThis"><?php echo $countLike;?></span> likes &bull; <i class='fa fa-thumbs-down'></i><?php echo $countDisLike;?> dislikes &bull;<i class='fa fa-thumbs-down'></i><a href='<?php echo base_url();?>index.php/photoCheese/deleteUploadPic/<?php echo $row['uploadID'];?>'>Delete Picture</a></p>
 <input type="button" onclick="getVal(this.value)" class='detailButton1' name='like_name' id='like_id' value='<?php echo $link;?>' title='Like this post'><i class='fa fa-thumbs-up'></i> Like</input>

使用Javascript：

function getVal(value) { jQuery.ajax({ type:"GET", url: "<?php echo base_url();?>index.php/photoCheese/like_total/", dataType:'json', data: {like_id : value}, success: function(res){ alert(res.no_likes); if(res){ jQuery("#likeThis").html(res.no_likes); } } });

控制器：

public function like_total(){
        $id = $this->session->userdata('userID');
        $upload = $this->input->get('like_id');
        $data = array('like' => 1,
                        'userID'=>$id,
                        'uploadID'=>$_GET['like_id']);

        $result = $this->photoCheese_model->get_like_total($data,$upload);


        return json_encode($result);
    }

型号：

public function get_like_total($data,$uplaod){
        $success = $this->db->insert('tbl_like',$data);

        if($success){
            $this->db->select('uploadID,SUM(`like`) as no_likes',false);
            $this->db->where('uploadID',$upload);
            $this->db->where('like !=',2);

            $query = $this->db->get();


        }
        return $query->result_array();
    }

此代码不会显示total_likes。这个怎么了？

Answer 1

这看起来像是一个不错的代码

public function like_total(){
    $id = $this->session->userdata('userID');
    $upload = $this->input->get('like_id');
    $data = array('like' => 1,
                    'userID'=>$id,
                    'uploadID'=>$_GET['like_id']);

    $result = $this->photoCheese_model->get_like_total($data,$upload);


    return json_encode($result);
}

只需一次尝试..改变你的

返回json_encode（$ result）

到

echo json_encode（$ result）

此示例可能会在将来帮助您jquery ajax php example

Answer 2

After all the helps and research. This is the running code of this problem.

In the View:

{!!\App\Library\TableHelper::colorText($product->number)!!}

Javascript:

<?php namespace App\Library; class TableHelper { public static function colorText($text) { switch ($text) { case '1' : $text = '<span color="green"> ' . $text . '</span>'; break; //... } return $text; } //to only get the color: public static function getColor($text) { switch ($text) { case '1' : return 'green' ; break; //... default: return 'white'; } } }

Controller:

<p id='state'><i class='fa fa-thumbs-up'></i><span class="likeThis"><?php echo $countLike;?></span> likes &bull; <i class='fa fa-thumbs-down'></i><?php echo $countDisLike;?> dislikes &bull;<i class='fa fa-thumbs-down'></i><a href='<?php echo base_url();?>index.php/photoCheese/deleteUploadPic/<?php echo $row['uploadID'];?>'>Delete Picture</a></p>
<input type="button" onclick="getVal(this.value)" class='detailButton1' name='like_name' id='like_id' value='<?php echo $link;?>' title='Like this post'><i class='fa fa-thumbs-up'></i> Like</input>

Model:

<script type="text/javascript">
    function getVal(value)
    {
      jQuery.ajax({
        type:"GET",
        url: "<?php echo base_url();?>index.php/photoCheese/like_total/",
        dataType:'json',
        data: {like_id : value},
        error: function(result){
              $('.likeThis').append('<p>goodbye world</p>');
              },
        success: function(result){
          jQuery(".likeThis").html(result);

        }
      });
    }
 </script>

This code runs perfectly now. Thanks for the help anyway.

Answer 3

试试这个。

public function like_total(){
    $id = $this->session->userdata('userID');
    $upload = $this->input->get('like_id');
    $data = array('like' => 1,
                    'userID'=>$id,
                    'uploadID'=>$_GET['like_id']);

    $no_likes = $this->photoCheese_model->get_like_total($data,$upload);

    $result['no_likes'] = $no_likes;

    $this->output->set_content_type('application/json')->set_output(json_encode($result)); 
}




public function get_like_total($data,$uplaod){
    $success = $this->db->insert('tbl_like',$data);

    if($success){
        $this->db->select('SUM(`like`) as no_likes');
        $this->db->where('uploadID',$upload);            

        $query = $this->db->get('tbl_like');

        $res = $query->row_array();

        return $res['no_likes'];
    }

    return 0;
}

Answer 4

public function like_total(){
$data = array('like' => 1,
                'userID'=>$this->session->userdata('userID'),
                'uploadID'=>$_GET['like_id']);

$no_likes = $this->photoCheese_model->get_like_total($data,$this->input->get('like_id'));

$result['no_likes'] = $no_likes;

 $this->output->set_content_type('application/json')->set_output(json_encode($result)); 
}




    public function get_like_total($data,$this->input->get('like_id')){
    $success = $this->db->insert('tbl_like',$data);

    if($success){
    $this->db->select('SUM(`like`) as no_likes');
    $this->db->where('uploadID',$this->input->get('like_id'));            

    $query = $this->db->get('tbl_like');

    $res = $query->row_array();

    return $res['no_likes'];
    }

    return 0;
    }

Answer 5

    public function article_search($search){

    $word = explode(' ',$search);   

    $query =  "select c.*,d.name,d.image_link from tbl_product as d inner join tbl_order as c on d.id=c.product_id
    where 1 and ";
    $i=1;
    foreach($word as $wd){
        if($i==1){
            $query.= "( c.customer like '%".$wd."%'";   
        }else{
            $query.=    " or c.customer like '%".$wd."%'";  
        }
        $i++;
    }

    foreach($word as $wd){
        if($i==1){
            $query.= "( c.order_no like '%".$wd."%'";   
        }else{
            $query.=    " or c.order_no like '%".$wd."%'";  
        }
        $i++;
    }
    foreach($word as $wd){
        if($i==1){
            $query.= "( d.name like '%".$wd."%'";   
        }else{
            $query.=    " or d.name like '%".$wd."%'";  
        }
        $i++;
    }
    foreach($word as $wd){
        if($i==1){
            $query.= "( d.commission like '%".$wd."%'"; 
        }else{
            $query.=    " or d.commission like '%".$wd."%'";    
        }
        $i++;
    }
    foreach($word as $wd){
        if($i==1){
            $query.= "( d.base_price like '%".$wd."%'"; 
        }else{
            $query.=    " or d.base_price like '%".$wd."%'";    
        }
        $i++;
    }

        $query.=    " or c.customer like '%".$search."%'";
        $query.=    " or c.order_no like '%".$search."%' ";
        $query.=    " or d.name like '%".$search."%' ";
        $query.=    " or d.commission like '%".$search."%' ";
        $query.=    " or d.base_price like '%".$search."%' )";

    $query = $this->db->query($query);
    //echo $this->db->last_query();die;

    $record = $query->result_array();
    foreach($record as $key=>$value){
        $cat       = $value['product_id'];
        $query_tag = $this->db->query("select * from tbl_product where  id in(".$cat.")");
        $record[$key]['all_pro'] = $query_tag->result_array();            
    }
    return $record;

}

使用Ajax动态显示数据

5 个答案: