Question

我有以下XML：

<?xml version="1.0" encoding="UTF-8"?>
<pp010 xmlns="http://www.123456768.com/technology">
<rptHdr>
<exchNam>MyXML</exchNam>
<envText>P</envText>
<rptCod>pp010</rptCod>
<rptNam>Daily Stock</rptNam>
<membLglNam>CompanyA</membLglNam>
<rptPrntEffDat>2015-04-14</rptPrntEffDat>
<rptPrntRunDat>2015-04-14</rptPrntRunDat>
</rptHdr>
<pp010Grp>
<pp010KeyGrp>
<membClgIdCod>HBGKP</membClgIdCod>
</pp010KeyGrp>
<pp010Grp1>
<pp010KeyGrp1>
<membExchIdCod>JBGJG</membExchIdCod>
</pp010KeyGrp1>
<pp010Grp2>
<pp010KeyGrp2>
<currTypCod>CHF</currTypCod>
</pp010KeyGrp2>
<pp010Grp3>
<pp010KeyGrp3>
<acctTypGrp>PP</acctTypGrp>
</pp010KeyGrp3>
<pp010Rec>
    <mgnGrpCod>     </mgnGrpCod>
    <mgnClsCod>CSLN </mgnClsCod>
    <mgnPremiumAmnt>+222926.00</mgnPremiumAmnt>
    <mgnLiqDlvAmnt>+0.00</mgnLiqDlvAmnt>
    <mgnSprdAmnt>+0.00</mgnSprdAmnt>
    <mgnAddlAmnt>+89349.30</mgnAddlAmnt>
    <unadjMgnReq>+312275.30</unadjMgnReq>
</pp010Rec>
<pp010Rec>
    <mgnGrpCod>     </mgnGrpCod>
    <mgnClsCod>CSLM </mgnClsCod>
    <mgnPremiumAmnt>+55112.00</mgnPremiumAmnt>
    <mgnLiqDlvAmnt>+0.00</mgnLiqDlvAmnt>
    <mgnSprdAmnt>+0.00</mgnSprdAmnt>
    <mgnAddlAmnt>+30854.40</mgnAddlAmnt>
    <unadjMgnReq>+85966.40</unadjMgnReq>
</pp010Rec>

我正在使用以下代码但似乎无法使用来自...的数据创建IEnumberable。

public class MarginRep
{
 public string mgnGrpCod {get;set;}
 public string mgnClsCod {get;set;}
 public string mgnPremiumAmnt {get;set;}
 public string mgnLiqDlvAmnt {get;set;}
 public string mgnSprdAmnt {get;set;}
 public string mgnAddlAmnt {get;set;}
 public string unadjMgnReq {get;set;}                      
    }

 private void button1_Click(object sender, EventArgs e)
 {
  string file =    @"D:\WorkDesktop\VisualStudio\file.xml";

  XDocument xmlDoc = XDocument.Load(file);

 IEnumerable<MarginRep> myMarginRep = 
 from c in xmlDoc.Descendants("pp010Rec")


            select new MarginRep()
            {
             mgnGrpCod = (string)c.Attribute("mgnGrpCod"),
             mgnClsCod = (string)c.Attribute("mgnClsCod"),
             mgnPremiumAmnt = (string)c.Attribute("mgnPremiumAmnt"),
             mgnLiqDlvAmnt = (string)c.Attribute("mgnLiqDlvAmnt"),
             mgnSprdAmnt = (string)c.Attribute("mgnSprdAmnt"),
             mgnAddlAmnt = (string)c.Attribute("mgnAddlAmnt"),
             unadjMgnReq = (string)c.Attribute("unadjMgnReq"),

                      };


    }

抱歉有大量的XML。我觉得我需要将它显示为我不需要的前几行，并且似乎无法向下导航pp010Rec

如果您能提供任何帮助，我将不胜感激，如果您能指出我可以花时间阅读并单独尝试的方向文献。

干杯，

Answer 1

您似乎希望值不是属性，因此请更改：

declare @idchar(2)
set @id= ''

select names from Units
where id in(    
    case @id
        when '' then (select id from Units)
        else @id
    end
)

要：

  mgnGrpCod = (string)c.Attribute("mgnGrpCod"),

对其他属性执行相同操作

Answer 2

我有点改变.xml：

<?xml version="1.0" encoding="UTF-8"?>
<pp010 xmlns="http://www.123456768.com/technology">
<rptHdr>
<exchNam>MyXML</exchNam>
<envText>P</envText>
<rptCod>pp010</rptCod>
<rptNam>Daily Stock</rptNam>
<membLglNam>CompanyA</membLglNam>
<rptPrntEffDat>2015-04-14</rptPrntEffDat>
<rptPrntRunDat>2015-04-14</rptPrntRunDat>
</rptHdr>
<pp010Grp>
<pp0510KeyGrp>
<membClgIdCod>HBGKP</membClgIdCod>
</pp0510KeyGrp>
<pp010Grp1>
<pp010KeyGrp1>
<membExchIdCod>JBGJG</membExchIdCod>
</pp010KeyGrp1>
<pp010Grp2>
<pp010KeyGrp2>
<currTypCod>CHF</currTypCod>
</pp010KeyGrp2>
<pp010Grp3>
<pp010KeyGrp3>
<acctTypGrp>PP</acctTypGrp>
</pp010KeyGrp3>
<pp010Rec>
    <mgnGrpCod>     </mgnGrpCod>
    <mgnClsCod>CSLN </mgnClsCod>
    <mgnPremiumAmnt>+222926.00</mgnPremiumAmnt>
    <mgnLiqDlvAmnt>+0.00</mgnLiqDlvAmnt>
    <mgnSprdAmnt>+0.00</mgnSprdAmnt>
    <mgnAddlAmnt>+89349.30</mgnAddlAmnt>
    <unadjMgnReq>+312275.30</unadjMgnReq>
</pp010Rec>
<pp010Rec>
    <mgnGrpCod>     </mgnGrpCod>
    <mgnClsCod>CSLM </mgnClsCod>
    <mgnPremiumAmnt>+55112.00</mgnPremiumAmnt>
    <mgnLiqDlvAmnt>+0.00</mgnLiqDlvAmnt>
    <mgnSprdAmnt>+0.00</mgnSprdAmnt>
    <mgnAddlAmnt>+30854.40</mgnAddlAmnt>
    <unadjMgnReq>+85966.40</unadjMgnReq>
</pp010Rec>

</pp010Grp3>
</pp010Grp2>
</pp010Grp1>
</pp010Grp>

</pp010>

所以你可以运行

public class MarginRep
    {
        public string mgnGrpCod { get; set; }
        public string mgnClsCod { get; set; }
        public string mgnPremiumAmnt { get; set; }
        public string mgnLiqDlvAmnt { get; set; }
        public string mgnSprdAmnt { get; set; }
        public string mgnAddlAmnt { get; set; }
        public string unadjMgnReq { get; set; }

        public override string ToString()
        {
            return string.Format("{0}\n{1}\n{2}\n{3}\n{4}\n{5}\n{6}",
             mgnGrpCod, mgnClsCod, mgnPremiumAmnt, mgnLiqDlvAmnt, mgnSprdAmnt,
             mgnAddlAmnt, unadjMgnReq);
        }
    }

    var xmlDoc = XDocument.Load("1.xml");
    XNamespace xn = xmlDoc.Root.Name.Namespace;
    IEnumerable<MarginRep> myMarginRep = xmlDoc.Root.Descendants(xn + "pp010Rec")
    .Select(c => new MarginRep()
        {
            mgnGrpCod = c.Element(xn + "mgnGrpCod").Value,
            mgnClsCod = c.Element(xn + "mgnClsCod").Value,
            mgnPremiumAmnt = c.Element(xn + "mgnPremiumAmnt").Value,
            mgnLiqDlvAmnt = c.Element(xn + "mgnLiqDlvAmnt").Value,
            mgnSprdAmnt = c.Element(xn + "mgnSprdAmnt").Value,
            mgnAddlAmnt = c.Element(xn + "mgnAddlAmnt").Value,
            unadjMgnReq = c.Element(xn + "unadjMgnReq").Value
        });
    foreach (var x in myMarginRep)
        Console.WriteLine(x);

打印：

CSLN
+222926.00
+0.00
+0.00
+89349.30
+312275.30

CSLM
+55112.00
+0.00
+0.00
+30854.40
+85966.40

<强>更新链接：http://rextester.com/UFLPQ70590

Answer 3

你确实需要做JAT在帖子中所说的关于将属性更改为元素的内容，但这并不是你的列表不是从XML创建的原因。这是命名空间（“xmlns =”http://www.123456768.com/technology“），它给你带来麻烦。我不确定你的XML文件试图通过它来实现什么，但是如果你删除它并且做JAT建议您的IEnumerable将开始填充。

有关命名空间的更多信息，您可以从w3查看此链接： http://www.w3schools.com/xml/xml_namespaces.asp

读取XML到linq对象，然后创建XML

3 个答案: