我从我的数据库中检索了用户列表,现在我想将它们添加到我的页面中。我试图使用表格显示用户,并确保它们每行出现四个,然后跳转到新行,但我不知道如何做到这一点。到目前为止,这是我的js文件。如果您还有其他需要,请告诉我。
var space = new Array("username", "user_id","address","state","postal_code","phone","email");
$(document).ready( function() {
var obj = '';
$.getJSON( "obtainUsers.php", function(data) {
var num = 1;
var json = JSON.stringify(data);
obj = jQuery.parseJSON(json);
var html = "";
var tot_obj = obj.length ;
var upper = (num*10)-1;
var lower = (num*10)-10;
var max = ( upper < tot_obj ) ? upper : tot_obj ;
html += "<div><table width:'100%'><tr>";
for (var i = lower; i <= max-1 ; i++ )
{
var toggle = i % 2;
var list_items = "";
columns.forEach( function(col)
{
if ( obj[i][col] != null ) {
if ( obj[i][col] !== "" )
{
if ( obj[i].level == 'NEW' ) {
list_items += "<div class='new_client'>";
list_items += obj[i][col] + "</div >";
}
else if( obj[i].level == 'RENEWAL' ) {
list_items += "<div class='renewing_client'>";
list_items += obj[i][col] + "</div >";
}
else if( obj[i].level == 'CURRENT' ) {
list_items += "<div class='current_client';>";
list_items += obj[i][col] + "</div >";
//console.log(obj[i][col]);
}
}
}
} );
list_items += "</br >";
if ( toggle == 0 )
{
html += "<td><div class='table_styles'> ";
html += list_items ;
//console.log(list_items);
html += "</div></td>";
console.log(html);
}
else
{
html += "<td><div class='table_styles'> ";
html += list_items;
html += "</div></td>";
}
}
html += "</tr> </table></div>";
$('.runninglist').html(html);
});
});
答案 0 :(得分:1)
var columns = ["username","user_id","address","state","postal_code","phone","email"];
var level_classes = {"NEW":"new_client", "RENEWAL":"renewing_client", "CURRENT":"current_client"};
$(document).ready( function() {
$.getJSON("obtainUsers.php", function(data) {
var $table = $('<table style="width: 100%;">');
var $tbody = $('<tbody>');
$table.append($tbody);
var $tr = null;
data.forEach(function(user, index){
if(index % 4 === 0) {
$tr = $('<tr>');
$tbody.append($tr);
}
$td = $('<td class="'+level_classes[user.level]+'">');
columns.forEach(function(col){
$td.append(user[col]);
$td.append($('<br>'));
});
$tr.append($td);
});
$('.runninglist').append($table);
});
});