Question

我有一个jbuilder来显示我的对象。

这看起来如何（部分）

o = @property_object

json.features o.property_object_feature_pack, :pool, :garage, terrace

这显示我下一步：

{
 features: {
  pool: {
   params: null,
   present: "false"
   },
  garage_parking: {
   params: null,
   present: "false"
   },
  terrace_balcony: {
   params: null,
   present: "true"
   }
 }
}

问题是我不希望在输出功能中显示 present：“false”。为了解决这个问题，我编写了下一个代码

json.features o.property_object_feature_pack, :pool if o.property_object_feature_pack.pool['present'] === "true"
json.features o.property_object_feature_pack, :garage_parking if o.property_object_feature_pack.garage_parking['present'] === "true"
json.features o.property_object_feature_pack, :terrace_balcony if o.property_object_feature_pack.terrace_balcony['present'] === "true"

它有效 - 但看起来很糟糕。怎么可以重构？

下一个问题是它可能是将来在ActiveRecord中添加的新功能，我想知道我们可以在不设置名称的情况下迭代o.property_object_feature_pack吗？（：pool，：garage_parking等..）

ps。 raw o.property_object_feature_pack

features: {
 id: 820,
 property_object_id: 56879,
 created_at: "2015-04-27T18:25:25.712Z",
 updated_at: "2015-04-27T18:25:25.712Z",
 pool: {
  params: null,
  present: "false"
 },
 garage_parking: {
  params: null,
  present: "false"
 },
 terrace_balcony: {
  params: null,
  present: "true"
 },
 av_apartments: {
  params: null,
  present: "false"
 }
}

更新

受#mudasobwa的启发，我创建了一个解决我问题的小助手方法

def features_list
    @property_object.property_object_feature_pack.as_json.select! do |_, v|
      v.is_a?(Hash) && v['present'] == 'true'
    end
  end

Answer 1

我不知道jbuilder是什么，但我建议将json转换为普通的ruby哈希，做任何你想做的事情并将其转换回json：

require 'json'
hash = JSON.parse what_you_got_from_builder
hash[:features].select! do |_, v| 
  !v.is_a?(Hash) || v[:present] == 'true' 
end
hash.to_json

在jbuider中显示之前检查哈希值，Ruby on Rails

1 个答案: