Question

我想在列表中添加区域，包含该国家/地区，区域和国家/地区模型之间的M2M关系。我不能得到国家代码的属性，它说“结肠预期”。如果条件错过了什么？

views.py

notification = Notification.objects.filter(**condition). \
    exclude(notification_user__in=users). \
    order_by('notificationType__priority', '-start_date')
notifications = []

for n in notification:
    print len(n.region.all())
    if len(n.region.all())==0:
        notifications.append(n)
    else:
        if (region.countries__in=country):
            notifications.append(n)

Notififcation models.py

class Notification(models.Model):
  title = models.CharField(max_length=75)
  description = models.TextField()
  start_date = models.DateTimeField()
  end_date = models.DateTimeField()
  application = models.ManyToManyField('Products.Application')
  notificationType = models.ForeignKey(NotificationType)
  url = models.URLField(null=True, blank=True)
  region = models.ManyToManyField('Geolocations.Region', null=True, blank=True)
  image = models.ImageField(null=True, blank=True)
  user = models.ManyToManyField(User, through='Notification_User')

Geolocations models.py

class Country(models.Model):
  code=models.CharField(max_length=2)
  name=models.CharField(max_length=36)
def __unicode__(self):
    return u'%s - %s' % (self.code, self.name)
class Meta:
    verbose_name_plural="Countries"

class Region(models.Model):
  name=models.CharField(max_length=10)
  countries=models.ManyToManyField(Country)

Answer 1

region.countries__in = country是一个赋值，因为它是在if语句的条件下执行的，所以你得到“冒号预期”。

如果您想检查与某个地区相关的国家/地区，请执行以下操作：

# country is the country's code
n.region.filter(countries_code=country).exists()

Django多对多过滤字段

1 个答案: