Question

我正在开发一个应用程序，必须将图像发送到外部服务器，下载并安装the file-transfer，但是它停止工作时出现错误3，我在本地网络上运行xampp，下面是我的代码，我从插件文档

中获取它

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
    <title>File Transfer Example</title>

    <script type="text/javascript" charset="utf-8" src="cordova.js"></script>
    <script type="text/javascript" charset="utf-8">

        // Wait for device API libraries to load
        //
        document.addEventListener("deviceready", onDeviceReady, false);

        // device APIs are available
        //
        function onDeviceReady() {
            // Retrieve image file location from specified source
            navigator.camera.getPicture(
                uploadPhoto,
                function(message) { alert('get picture failed'); },
                {
                    quality         : 50,
                    destinationType : navigator.camera.DestinationType.FILE_URI,
                    sourceType      : navigator.camera.PictureSourceType.PHOTOLIBRARY
                }
            );
        }

        function uploadPhoto(imageURI) {
            var options = new FileUploadOptions();
            options.fileKey="file";
            options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
            options.mimeType="image/jpeg";

            var params = {};
            params.value1 = "test";
            params.value2 = "param";

            options.params = params;

            var ft = new FileTransfer();
            ft.upload(imageURI, encodeURI("http://192.168.0.105/upload/index.php"), win, fail, options);
        }

        function win(r) {
            console.log("Code = " + r.responseCode);
            console.log("Response = " + r.response);
            console.log("Sent = " + r.bytesSent);
        }

        function fail(error) {
            alert("An error has occurred: Code = " + error.code);
            console.log("upload error source " + error.source);
            console.log("upload error target " + error.target);
        }

        </script>
</head>
<body>
    <h1>Example</h1>
    <p>Upload File</p>
</body>
</html>

PHP：

<?php
$new_image_name = strtolower($_FILES['file']['name']);
move_uploaded_file($_FILES["file"]["tmp_name"], "images/".$new_image_name);

Answer 1

将标题对象添加到选项一次。来自here

的解决方案

options.headers = { 连接：＆＃34;关闭＆＃34; }

错误3文件传输Cordova

1 个答案: