wicket

Question

    private ArrayList<MFRList> list;
private ArrayList<STUList>  list1 = new ArrayList<STUList>();


public ResultPage(PageParameters params) throws APIException {

 Form form = new Form("form");
    PageableListView view = new PageableListView("view", list, 10) {

        @Override
        public void onConfigure() {
            super.onConfigure();
            setVisible(list.size() > 0);
        }

        @Override
        protected void populateItem(ListItem item) {

            final StuList stu= (StuList) item.getModelObject();
            item.add(new CheckBox("check", item.getModel()));
            item.add(new Label("name", stu.getName()));
            item.add(new Label("num", stu.getNumber()));
            item.add(new Label("age", stu.getAge()));
            item.add(new Label("sex", stu.getSex()));
        }
    };

    Button backtosearchbutton = new Button("backtosearchbutton") {

        @Override
        public void onSubmit() {
            setResponsePage(SearchPage.class);
        }
    }.setDefaultFormProcessing(false);
    Button groupcheckbutton = new Button("groupcheckbutton") {

        @Override
        public void onSubmit() {
        }
    }.setDefaultFormProcessing(false);
    Button groupuncheckbutton = new Button("groupuncheckbutton") {

        @Override
        public void onSubmit() {
        }
    }.setDefaultFormProcessing(false);
    Button submitselectionbutton = new Button("submitselectionbutton") {

        @Override
        public void onSubmit() {
        }
    }.setDefaultFormProcessing(true);
    form.add(view);
    form.add(backtosearchbutton);
    form.add(submitselectionbutton);
    form.add(groupuncheckbutton);
    form.add(groupcheckbutton);
    add(form);
    add(new CustomPagingNavigator("navigator", view));

如何存储所选记录以及如何使用它。我明白，在提交表格时，这些记录已提交，但我不清楚如何以及在何处。

和我的pojo是

public class MFRList implements Serializable {

private String name;
private String num;
private String age;
private String sex;
private Boolean selected = Boolean.FALSE;

public String getName() {
    return Name;
}

public void setName(String Name) {
    this.Name = Name;
}

public String getnum() {
    return num;
}

public void setnum(String num) {
    this.num = num;
}

public String getAge() {
    return age;
}

public void setsex(String sex) {
    this.sex= sex;
}

public String getsex() {
    return sex;
}

public void setage(String age) {
    this.age = age;
}

public Boolean getSelected() {
    return selected;
}

public void setSelected(Boolean selected) {
    this.selected = selected;
}

}

保存所选行的位置以及如何检索和使用它。

先谢谢

Answer 1

您应该使用带有支票的CheckGroup：

public ResultPage（PageParameters params）抛出APIException {

Form form = new Form("form");

CheckGroup selection = new CheckGroup("selection", new ArrayList());
selection.setRenderBodyOnly(false);
form.add(selection);

PageableListView view = new PageableListView("view", list, 10) {

    @Override
    public void onConfigure() {
        super.onConfigure();
        setVisible(list.size() > 0);
    }

    @Override
    protected void populateItem(ListItem item) {

        final StuList stu= (StuList) item.getModelObject();
        item.add(new Check("check", item.getModel()));
        item.add(new Label("name", stu.getName()));
        item.add(new Label("num", stu.getNumber()));
        item.add(new Label("age", stu.getAge()));
        item.add(new Label("sex", stu.getSex()));
    }
};
selection.add(view);

这样传递给CheckGroup构造函数的arrayList将始终包含所选对象。

Answer 2

我得到了我想要实现的目标，但如果它是最佳解决方案，我就不会这样做。

我创建了自己的模型，并在选中复选框时将对象添加到列表中。 class SelectedCheckBoxModel扩展AbstractCheckBoxModel {

  private final STUList info; 
  private ArrayList<STUList> list1; 

public SelectedCheckBoxModel(STUList info, ArrayList<STUList> list1) {
    super();
    this.info = info;
    this.list1 = list1;
}

@Override
public boolean isSelected() {
    // TODO Auto-generated method stub
     return list1.contains(info); 
}

@Override
public void select() {
    // TODO Auto-generated method stub
    list1.add(info); 

}

@Override
public void unselect() {
    // TODO Auto-generated method stub
    list1.remove(info);

}

我在我的listview中调用它

check = new CheckBox("check", new SelectedCheckBoxModel(stu, list1));
item.add(check);

如果这不是最佳，请建议

谢谢