经过一段时间(2分钟),当我尝试使用javascript提交表单时,它只提交没有发布数据值的表单!在网上搜索解决方案但无法找到解决方案!!希望有人能帮助我
代码:
<script type="text/javascript">
$(function() {
$('.countdown.callback').countdown({
date: +(new Date) + 120000,
render: function(data) {
$(this.el).text( this.leadingZeros(data.min, 2) + "min " + this.leadingZeros(data.sec, 2) + " sec");
if(this.leadingZeros(data.min, 2) < 01 && this.leadingZeros(data.sec, 2) <= 10){
$(this.el).addClass('ended');
}
},
onEnd: function() {
document.getElementById('myform').submit();
}
});
});
</script>
使用php的HTML代码
<?php
foreach($row as $r){
if(!empty($r['question'])){
?>
<form method="post" id="myform" action="subanswer.php" >
<p><span style="color:rgb(33,79,157);"><?php echo $r['id'];?> <?php echo $r['question'];?></span><br />
<input type="radio" name="<?php echo $r['test_id'].'_'.$r['id'];?>" value="<?php echo $r['ans1'];?>"> <?php echo $r['ans1'];?>
<br>
<input type="radio" name="<?php echo $r['test_id'].'_'.$r['id'];?>" value="<?php echo $r['ans2'];?>"> <?php echo $r['ans2'];?>
<br>
<input type="radio" name="<?php echo $r['test_id'].'_'.$r['id'];?>" value="<?php echo $r['ans3'];?>"> <?php echo $r['ans3'];?>
<input type="hidden" name="testname" value="<?php echo $_GET['id']?>">
</p>
<?php
}
}
?>
<input type="submit" name="subans" value="add" class="but" style="width:15%;" />
</form>
答案 0 :(得分:0)
从您的代码中,您似乎正在调用错误的表单:
document.getElementById('myForm').submit();
ID myFom
不存在。你有:
<form method="post" id="myform1" action="subanswer.php" >
也不确定为什么人们不会始终坚持使用JQuery。建议:
$("#myForm1").submit();