我有一个像这样的数据帧(df2):
locus transect fq d
Locus_1 A 0.000 20
Locus_1 A 0.000 35
Locus_1 A 0.000 50
Locus_2 A 0.200 20
Locus_2 A 0.083 35
Locus_2 A 0.125 50
Locus_3 A 0.134 20
Locus_3 A 0.208 35
Locus_3 A 0.218 50
Locus_4 A 0.000 20
Locus_4 A 0.000 35
Locus_4 A 0.000 50
Locus_5 A 0.100 20
Locus_5 A 0.000 35
Locus_5 A 0.038 50 ...
基本上每个基因座沿着与中心不同距离的样带被采样三次。有成千上万的基因座。 从这个数据集中,我计算出频率和距离之间的相关性。
接下来的步骤是:
我主要使用Plyr
和dplyr
。
这是我提出的代码:
df3 <- group_by(df2, transect, locus) #setting up groups to which apply functions
data <- replicate(1000, {
test <- sample_n(df3, 3, replace=F) #shuffle by group
Rho <- ddply(test, .(transect, locus), summarise, corr= cor(fq, d, method = "spearman")) #calculate correlation
Rho[is.na(Rho)] <- 0 #replacing missing values with zero
Rho_mean_bylocus <- ddply(Rho, .(locus), summarise, mean=mean(corr)) #average correlation over transect
}, simplify = TRUE)
结果如下:
[,1] [,2] [,3] [,4]
locus factor,978 factor,978 factor,978 factor,978
mean Numeric,978 Numeric,978 Numeric,978 Numeric,978
[,5] [,6] [,7] [,8]
locus factor,978 factor,978 factor,978 factor,978
mean Numeric,978 Numeric,978 Numeric,978 Numeric,978
[,9] [,10]
locus factor,978 factor,978
mean Numeric,978 Numeric,978
(我有978个位点)。
我尝试在函数
中嵌入replicate()
rand.rho <- function(x) { #I have tried also without using a function, but still does not work
data <- replicate(1000, {
test <- sample_n(df3, 3, replace=F) #shuffle
Rho <- ddply(test, .(transect, locus), summarise, corr= cor(fq, d, method = "spearman")) #calculate correlation
Rho[is.na(Rho)] <- 0 #replacing missing values with zero
Rho_mean_bylocus <- ddply(Rho, .(locus), summarise, mean=mean(corr)) #average correlation over transect
}, simplify = TRUE)
df4 <- rand.rho(df3)
但是我收到了错误:
Error in list_to_dataframe(res, attr(.data, "split_labels"), .id, id_as_factor) :
Results must be all atomic, or all data frames
In addition: There were 50 or more warnings (use warnings() to see the first 50)
我很茫然。
我已经在这里寻找其他答案,并尝试实施该建议,但它仍然无效。
有什么建议吗?