Question

我在SQL Server中有一个看起来像这样的查询。

SELECT   
    [ActionId], [CreationDate], [Description]     
FROM 
    [Action]
INNER JOIN
    People ON Action.personid = People.personid
WHERE
    datediff(mm, Action.creationdate, getdate()) = 1 
    AND People.typeofpersonid = 8

但现在我想删除任何在一分钟内创建时间的响应。

因此，如果当前的回复是

ActionId CreationDate                  Description
---------------------------------------------------------
510467   2015-04-07 11:21:02.030       Registered errand.
510468   2015-04-07 11:21:25.840       Email sent to:....
510477   2015-04-07 11:50:22.830       Registered errand.

我希望第二行不会被退回。

有没有聪明的方法来做到这一点？

Answer 1

你需要这样的东西：

SELECT  [ActionId],   [CreationDate],    [Description]     
         FROM [Action]
         inner join People on Action.personid = People.personid
         where datediff(mm, Action.creationdate, getdate()) = 1 
         and      People.typeofpersonid=8

    AND  NOT EXISTS 
    (
    SELECT TOP 1 1
    FROM [Action] Ain
         inner join People Pin on Ain.personid = Pin.personid
         where datediff(mm, Ain.creationdate, getdate()) = 1 
         and      Pin.typeofpersonid=8
         AND datediff(mi, Ain.creationdate, Action.creationdate)<1
         AND Ain.ActionId <>Action.ActionId
    )

一般的想法是你检查现有的行，如果有的话，那么你不要在查询中包含它。

Answer 2

这应该有效：

SELECT
    Action.ActionId,
    Action.CreationDate,
    Action.Description
FROM 
    Action
JOIN
(
    SELECT 
        ActionId, 
        ROW_NUMBER() OVER (
            PARTITION BY LEFT(CONVERT(VARCHAR, CreationDate, 120), 16)
            ORDER BY CreationDate, ActionId
        ) AS row_num
    FROM 
        Action
    WHERE
        DATEDIFF(mm, CreationDate, GETDATE()) = 1 
) AS a2 ON (Action.ActionId = a2.ActionId AND a2.row_num = 1)
JOIN 
    People ON (Action.PersonDd = People.PersonId)
WHERE 
    DATEDIFF(mm, Action.CreationDate, GETDATE()) = 1 
    AND People.TypeOfPersonId = 8

SQL Server：删除几乎相同日期的响应

2 个答案: